The circumference of a circle is given by: 2πr, where r is the radius of the circle. Equating 4π, we have 2πr = 4π so the radius of the circle is: r = 4/2 = 2. Then, the area of the circle is given by πr ^ 2 = π * (2 ^ 2) = 4π.Since the square and the circle have the same area, then: Let L be the side of the square, we have: L ^ 2 = 4π, clearing L = 2 * (π ^ (1/2))The perimeter of a square is the sum of its sides: P = L + L + L + L = 2 * (π ^ (1/2)) + 2 * (π ^ (1/2)) + 2 * (π ^ (1/2)) + 2 * (π) ^ (1/2)) P = 8 * (π ^ (1/2))
Answer:
(6, 0 )
Step-by-step explanation:
A translation to the left means subtract 2 from the x- coordinate
A translation down means subtract 4 from the y- coordinate
Then
(8, 4 ) → (8 - 2, 4 - 4 ) → (6, 0 )
Hi there!
Using the formula - n-2*180 -, we know that the interior angles of a pentagon add up to 540. We can use the values we're given and add them together and set them all equal to 540, then solve.
WORK:
540 = 204 + 12x
336 = 12x
x = 28
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Answer:
Width
Step-by-step explanation:
When we have quantitative data it is grouped in classes. There are three ways in which the data can be grouped they are:
Single value grouping where each class has one distinct value.
In Cutpoint grouping is used when the observations have decimal points
In Limit grouping a classes are set based on a specified range of values. Here limit grouping is being done and the range of each class is called width.
(11a+6)-(7a+12) should equal 18a-6 in simplest form.