Question

LeAnn is purchasing giftwrap for a box that measures 8 inches long, 6 inches wide, and 6 inches tall. Calculate the total area of the box that will be covered in gift wrap. Show all of your work for full credit.

Answer 1

Let

L---------> the length side of the box

W--------> the width side of the box

H-------> the height of the box

we know that

$L=8\ in\\W=6\ in\\H=6\ in$

the surface area of the box is equal to

$S=2*area\ of\ the\ base+perimeter\ of\ the\ base*H$

Find the area of the base

$A=L*W=8*6=48\ in^{2}$

Find the perimeter of the base

$P=2*L+2*W=2*8+2*6=28\ in$

Find the surface area

$S=2*48+28*6$

$S=264\ in^{2}$

therefore

the answer is

the total area of the box that will be covered in gift wrap is $264\ in^{2}$

Answer 2

A box shape in three dimensional space. Formally, a polyhedron for which all faces are rectangles. 
Rectangular Parallelepiped
Volume = lwh 8*6*6=288Lateral Surface Area = 2lh + 2wh=94Surface Area = 2lw + 2lh + 2wh=288