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Dmitry [639]
3 years ago
14

Lee watches tv 3hours per day. Lee tv consumes 200 watts when on. Electricity cost 12 cents 1 kilowatt-hour how much does Lee's

tv cost to operate for 30 days
Mathematics
2 answers:
kotykmax [81]3 years ago
5 0

Answer:

The cost of operating a 200-Watt TV 3 hours per day for 30 days is 2.16 dollars.

Step-by-step explanation:

This problem ask us for the total cost associated with electricity consumption in a period of time. Hence, the total cost of energy is obtained by making appropriate conversions, that is:

Cost = Energy consumed x Time x Unit cost

C = (200\,W) \cdot (30\,days) \cdot \left(3\,\frac{h}{day} \right)\cdot \left(3600\,\frac{s}{h}\right) \cdot \left(\frac{1}{3600000} \,\frac{kWh}{J}\right)\cdot \left(0.12\,\frac{USD}{kWh} \right)

C = 2.16\,USD

The cost of operating a 200-Watt TV 3 hours per day for 30 days is 2.16 dollars.

Alik [6]3 years ago
3 0

Answer: $2.16

Lee watches TV 3 hours per day and TV consumes 200 watts.

Cost of electricity = 12 cents/(1-kilowatt-hour)

200w×3 hours

600 watt-hours

1000 watt-hours=1kwh

1 watt-hours= 1/1000 kwh

600 watt-hours 600/1000=0.6 kwh

0.6×12=7.2cents

1 day=7.2 cents

30 days

7.2×30

216 cents

$2.16

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Answer:

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Step-by-step explanation:

Goods available for sale = beginning inventory + Merchandise Purchases

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6 0
3 years ago
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oee [108]

Answer:

a couple of irrational numbers: -16±4√19, approximately {1.436, -33.436}

Step-by-step explanation:

Your question can be cast as the quadratic equation

  x² +32x -48 = 0

The solutions can be found using the quadratic formula:

  x = (-32 ±√(32² -4(1)(-48)))/(2(1)) = -16±√304 = -16±4√19

_____

<em>Comment on the equation we used</em>

We notice that when p and q are roots, the equation can be written ...

  (x -p)(x -q) = 0 = x² -(p+q)x +pq

You want p+q = -32, pq = -48, so the equation is ...

  x² -(-32)x +(-48) = 0

  x² +32x -48 = 0 . . . . . . with parentheses eliminated

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