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N76 [4]
3 years ago
6

Identify the variables in the expression 4mn + 6m - 3

Mathematics
1 answer:
pychu [463]3 years ago
4 0

Hey there! I'm happy to help!

A variable is a letter or symbol used to represent an unknown number.

We see two letters here: m and n. Therefore, those are the variables.

Have a wonderful day! :D

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Assume that you assign the following subjective probabilities for your final grade in your econometrics course (the standard GPA
rodikova [14]

Answer:

E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78

So then the best answer for this case would be:

C. 2.78

Step-by-step explanation:

For this case we have the following probabability distribution function given:

Score         P(X)

A= 4.0       0.2

B= 3.0       0.5

C= 2.0       0.2

D= 1.0        0.08

F= 0.0       0.02

______________

Total          1.00

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

If we use the definition of expected value given by:

E(X) = \sum_{i=1}^n X_i P(X_I)

And if we replace the values that we have we got:

E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78

So then the best answer for this case would be:

C. 2.78

3 0
3 years ago
If h(x) = -4x - 10, find h(-5)
Neko [114]

Answer:

zero.

Step-by-step explanation:

. Here are the steps. h(x) = -5x - 10. h(-2) = -5(-2) - 10. h(-2) = 10 - 10. h(-2) = 0. Have a great day

4 0
2 years ago
Read 2 more answers
How do i rearrange the formula <br><br> w = x^2 - 2yz<br><br> to make y the subject?
iogann1982 [59]
Solve for y by simplifying both sides of the equation, then isolating the variable.
y = x^2/2^z - w/2z
7 0
3 years ago
I don’t know the answer and I’m panicking help!!
Nonamiya [84]

Answer:

I think it may be the first one or the 3rd one! GOOD LUCK

7 0
3 years ago
Determine the number of real solutions for the equation: 6x^2+8x=7
densk [106]

Answer:

Step-by-step explanation:

You could factor this to find out how many real roots you have, but it's easier to use the rule of the discriminate.  The discriminate comes from the quadratic formula:

b^2-4ac

Plug in the numbers from the quadratic and see what the value of it is.  If the:

discriminate < 0, you have 2 imaginary roots

discriminate = 0, you have 1 real root, multiplicity 2 and

discriminate > 0, you have 2 real roots

Our b is 8, our a is 6 and our c is -7 (remember you have to set the polynomial equal to 0 to do this).

8^2-4(6)(-7)=232

Because 232 is > 0, we have 2 real roots.

7 0
3 years ago
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