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Temka [501]
4 years ago
14

30 PTS 30 PTS 30 PTS 30 PTS

Mathematics
2 answers:
BARSIC [14]4 years ago
8 0

Answer:

the first two are equations and the last one is a solution

Step-by-step explanation:

wariber [46]4 years ago
5 0
1 and 2 are equations and 3 is a solution
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Explain how to graph y > 2x + 3
Leona [35]

>; < - dot line

≥; ≤ - solid line

>; ≥ - shading above the line

<; ≤ - shading below the line

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y = 2x + 3 - it's a linear function. We only need two points to plot the graph. Select two any x values and calculate the y values:

for x = 0 → y = 2(0) + 3 = 0 + 3 = 3 → (0, 3)

for x = -2 → y = 2(-2) + 3 = -4 + 3 = -1 → (-2, -1)

y > 2x + 3

Dot line an shading above the line (look at the picture).

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4 years ago
I am confused on how to find the equation for parallel and perpendicular lines and the line parallel and perpendicular to it
Svetach [21]

Answer:

Hello what grade is this for?

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3 years ago
Can you help me you can do only a
Dominik [7]
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5 0
3 years ago
A 20 ounce box of cereal costs $3.20. A 12 ounce box of cereal costs $1.80. Which box of cereal is the better buy?
lisov135 [29]
Use Socratic it always works usually but it’s faster
5 0
3 years ago
Match the range of the function f(x) = x2 + 2x − 1 to its domain.
Kamila [148]
F(x) = x² + 2x - 1

f(2) = 2² + 2 · 2 - 1 = 4 + 4 - 1 = 7
f(-2) = (-2)² + 2 · (-2) - 1 = 4 - 4 - 1 = -1
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f(-3) = (-3)² + 2 · (-3) - 1 = 9 - 6 - 1 = 2

The range = {-1; 2; 7; 14}
5 0
3 years ago
Read 2 more answers
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