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umka21 [38]
3 years ago
14

Makato and his friends rolled two fair number cubes 500 times and recorded the sum of the numbers shown on the cubes each time.

On 42 of the trials the sum was 10. Which of these is most likely the probability that the sum of the numbers shown on the cube is 10 when two fair number cubes are rolled?
Mathematics
1 answer:
denpristay [2]3 years ago
8 0

Answer:

2:12

Step-by-step explanation:

6 and 4 = 10

5 and 5 = 10

You might be interested in
What is the graph of the equation y-3=2(x+3)
arsen [322]

Answer:

y−3=2(x+3)

y=2x+9

that's the answer hope this helps u

5 0
2 years ago
Diego said that the awnser to the question "How many groups of 5/6 are in 1?" Is 6/5 or 1 1/5.Do you agree with his statement? E
slamgirl [31]

Answer:

Diego is correct.

He has correctly divided 1 in groups of \frac{5}{6}.

Step-by-step explanation:

The question 'How many groups of 5/6 are in 1?'  means that we need to divided 1 into groups of \\frac{5}{6}.

When we form groups from a given total, we divided the total by the size of the group.

If we are dividing N number of people in groups of x number of people, then the expression to find the number of groups formed can be given as:

⇒ \frac{N}{x}

For this question the data given is:

N=1

x=\frac{5}{6}

So, the number of groups formed can be given as:

⇒ \frac{1}{\frac{5}{6}}

When divisor is a fraction, then we multiply the reciprocal of the divisor with the dividend.

⇒ 1\times\frac{6}{5}

⇒ \frac{6}{5}

In order to convert fraction to mixed number we will divide numerator with denominator and then write the quotient as whole number, remainder as numerator and the denominator remains as it is.

On dividing 6 by 5, the quotient =1 and remainder =1. Thus the mized number is:

⇒ 1\frac{1}{5}

Thus, there are \frac{6}{5} or 1\frac{1}{5} groups in 1. This matches with Diego's answer and hence he is correct.

3 0
3 years ago
Two terms of an arithmetic sequence are a10=16 and a35=66 find the sum of the first 75 terms
andrew11 [14]

The sum of the first 75 terms of the arithmetic sequence that has 10th term as 16 and the 35th term as 66 is 5400.  

<h3>How to find the sum of terms using Arithmetic sequence formula</h3>

aₙ = a + (n - 1)d

where

  • a = first term
  • d = common difference
  • n = number of terms

Therefore, let's find a and d

a₁₀ = a + (10 - 1)d

a₃₅ = a + (35 - 1)d

Hence,

16 = a + 9d

66 = a + 34d

25d = 50

d = 50 / 25

d = 2

16 - 9(2) = a

a = 16 - 18

a  = -2

Therefore, let's find the sum of 75 terms of the arithmetic sequence

Sₙ = n / 2 (2a + (n - 1)d)

S₇₅ = 75 / 2 (2(-2) + (75 - 1)2)

S₇₅ = 37.5 (-4 + 148)

S₇₅ = 37.5(144)

S₇₅ = 5400

learn more on arithmetic sequence here: brainly.com/question/1687271

4 0
2 years ago
Can someone help I will give the brainliest Plz help u will get 50 points
lara [203]

Answer:

B.) 6

2.) 70

3.) 56

Step-by-step explanation:

B.) 2(6) - 6

= 12 - 6

=6

2.) 7(2(3)+4)

=7(6+4)

=42+28

=70

3.) 10(3) + 4(3) + 14

= 30 + 12 + 14

= 42+14

=56

Have a wonderful day

:)

7 0
3 years ago
The lines shown below are perpendicular. If the green line has a slope of
DedPeter [7]
The opposite reciprocal of -1/9 is 9
So the answer is A
3 0
3 years ago
Read 2 more answers
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