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zavuch27 [327]
2 years ago
6

The equation cos (35 degree)= a/25 can be used to find the length of Line segment B C. Triangle A B C is shown. Angle A C B is a

right angle and angle C B A is 35 degrees. The length of C B is a and the length of hypotenuse A B is 25 inches. What is the length of Line segment B C? Round to the nearest tenth. 14.3 in. 20.5 in. 21.3 in. 22.6 in.

Mathematics
2 answers:
labwork [276]2 years ago
6 0

Answer:

<u>20.5 Inches</u>

Step-by-step explanation:

I just took the review so this is a verified answer.

KengaRu [80]2 years ago
5 0

Answer:

20.5

Step-by-step explanation:

cos(35) = a/25

(25)cos(35) = a/25(25)

20.5 = a

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3 years ago
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Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu
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<u>Answer-</u>

<em>The polynomial function is,</em>

y=x^4-10x^3+38x^2-64x+40

<u>Solution-</u>

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))   ( ∵ (3-i) is the conjugate of (3+i) )

\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)

\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)

\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)

\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)

\Rightarrow y=(x^2-4x+4)(x^2-6x+10)

\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10

\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40

\Rightarrow y=x^4-10x^3+38x^2-64x+40

Therefore, this is the required polynomial function.


4 0
3 years ago
Amélie runs a bakery. She wants to find out whether her cake sales are affected by the weather conditions. She recorded the dail
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Answer:

Step-by-step explanation:

Daily temp(in F) Cakes sold

 

42 39

45 52

48 31

54 61

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To find whether there is an association between these two let us find the correlation coefficient between these two variables.

r=-0.1975

Since |r|<0.5, correlation is weak.  

Let us test the hypothesis r =0

H0:r=0

Ha:r not equals 0

Test statistic = \frac{r\sqrt{n-2} }{\sqrt{1-r^2} } \\=\frac{-0.1975\sqrt{11-2} }{\sqrt{1-0.1975^2} }\\=\frac{-0.5625}{{0.9803} } \\=-0.5738

p =0.298

Since p value >0.10, at 90% significance level we accept that there is no association.

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Answer:

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Describe the differences between vertical and adjacent angles
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