Answer:
60162.3214286
Step-by-step explanation:
that's just what my calculator said
Complete question :
Ray starts walking to school at a rate of 2 mi/h. Ten minutes later, his sister runs after him with his lunch, averaging 6mi/h. Determine take it takes for sister to catch up
Answer:
5 minutes
Step-by-step explanation:
Ray's rate = 2mi/ hr
Time walked before sister starts = 10 minutes = (10/60) = 0.16667 hours
Hence, distance already covered = (rate * time) = (2 * 0.16667) = 0.3333 miles
To catchup :
Let t = Time taken to catch ; At t, distance covered must be the same ; thus ;
0.3333 + (2 * t) = 6 * t
0.3333 + 2t = 6t
0.3333 = 6t - 2t
0.3333 = 4t
t = 0.3333 / 4
t = 0.0833333 hours
t = 0.0833333 * 60 = 5 minutes
The exponent for that would be 13^3.
If the answer is incorrect, then i am sorry.
Answer:
x=28
y= -4
Step-by-step explanation:
9x+6y= -12
-x-4y= -12
multiply -x-4y=-12 by 9 so the x's are equal
9x+6y= -12
-9x-36y= -108
add the equations so the x's cancel out
-30y=120
y= -4
plug y into an equation to find x
-x-4(-4)=-12
-x+16= -12
-x= -28
x=28
Answer:
10
Step-by-step explanation:
5 / .5 = 10