Answer:
Friction, Applied Force and Gravity
The efficiency of the first Carnot engine is
n1 = 1 - Th/T
The efficiency of the second Carnot engine is
n2 = 1 - T/Tc
The total efficiency of the engines put in series is
n = 1 - Th/Tc
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The equation to be used is the derived formulas for rectilinear motion at a constant acceleration. The formula for acceleration is
a = (v - v₀)/t
where
v and v₀ are the initial and final velocities, respectively
t is the time
a is the acceleration
Since it started from rest, v₀ = 0. Using the formula:
0.15 m/s² = (v - 0)/[2 minutes*(60 s/1 min)]
Solving for v,
v = 18 m/s
Like . . . repel
unlike . . . attract
positive . . . repel
negative . . . repel
Answer:
The maximum electric field strength = 0.01 V/m
Explanation:
Given
ΔV(max) = 4.00 mV = 0.004 V
d = 0.400 m
f = 1.00 Hz
Maximum electric field = (maximum potential)/(length)
Maximum electric field = E(max)
Maximum potential = 4.00 mV = 0.004 V
Length = 0.400 m
E(max) = (0.004/0.4) = 0.01 V/m
Hope this Helps!!!