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777dan777 [17]
3 years ago
5

An 85 kg object is moving at a constant speed of 15 m/s in a circular path, which has a radius of 20 meters. What centripetal fo

rce is exerted on the body? A. 42.50 N B. 765.00 N C. 63.75 N D. 956.25 N
Physics
1 answer:
UNO [17]3 years ago
7 0
As we know that centripetal force =mv^2/r
given data is 
m = mass
v = speed
r = radius
putting values we get

= 85 x 15^2 / 20

= 956.25 N
option d is correct
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Which of the following accurately describe some aspect of gravitational waves? Select all that apply.
steposvetlana [31]
<h2>Answers:</h2>

-The first direct detection of gravitational waves came in 2015

-The existence of gravitational waves is predicted by Einstein's general theory of relativity

-Gravitational waves carry energy away from their sources of emission

<h2>Explanation:</h2>

Gravitational waves were discovered (theoretically) by Albert Einstein in 1916 and "observed" for the first time in direct form in 2015 (although the results were published in 2016).  

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In this context, an excellent example is the system of two neutron stars that orbit high speeds, producing a deformation that propagates like a wave,<u> in the same way as when a stone is thrown into the water</u>. So, in this sense, gravitational waves carry energy away from their sources .

Therefore, the correct options are D, E and F.

5 0
4 years ago
Wanda has a cube of sugar. She crushes it into a powder. What has changed about the sugar?
stira [4]
Mass always stays the same therefore it can’t be c and d. Volume stays the same because she is not removing anything. Therefore it is a
5 0
3 years ago
Read 2 more answers
The base unit prefix used for 1,000× is _____. kilo milli centi deka
san4es73 [151]

Answer:

\Large \boxed{\sf kilo}

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kilo is a prefix that means 1000 of the base unit.

5 0
3 years ago
A pulley system has an efficiency of 87.5 percent.
Gelneren [198K]

Answer:

work done on desk = m g h = 105 * 9.81 * 2.46 = 2534 Joules

Explanation:

so work in = 2534 / 0.875 = 2896 Joules

that is your 648 times distance your hand moved holding the rope

2896 = 648 * x

4.47 meters

I think maybe a typo, 648 N is too big, maybe 64.8 ? Any block and tackle system does better than that.

7 0
2 years ago
A (B + 25.0) g mass is hung on a spring. As a result, the spring stretches (8.50 A) cm. If the object is then pulled an addition
Morgarella [4.7K]

Answer:

Time period of the osculation will be 2.1371 sec

Explanation:

We have given mass m = (B+25)

And the spring is stretched by (8.5 A )

Here A = 13 and B = 427

So mass m = 427+25 = 452 gram = 0.452 kg

Spring stretched x= 8.5×13 = 110.5 cm

As there is additional streching of spring by 3 cm

So new x = 110.5+3 = 113.5 = 1.135 m

Now we know that force is given by F = mg

And we also know that F = Kx

So mg=Kx

K=\frac{mg}{x}=\frac{0.452\times 9.8}{1.135}=3.90N/m

Now we know that \omega =\sqrt{\frac{K}{m}}

So \frac{2\pi }{T} =\sqrt{\frac{K}{m}}

\frac{2\times 3.14 }{T} =\sqrt{\frac{3.90}{0.452}}

T=2.1371sec

8 0
3 years ago
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