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777dan777 [17]
3 years ago
5

An 85 kg object is moving at a constant speed of 15 m/s in a circular path, which has a radius of 20 meters. What centripetal fo

rce is exerted on the body? A. 42.50 N B. 765.00 N C. 63.75 N D. 956.25 N
Physics
1 answer:
UNO [17]3 years ago
7 0
As we know that centripetal force =mv^2/r
given data is 
m = mass
v = speed
r = radius
putting values we get

= 85 x 15^2 / 20

= 956.25 N
option d is correct
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Acceleration can be found using a speed-time graph. true or false.
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Speed can be shown on a graph of position versus time, and acceleration can be shown on a graph of speed versus time.
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3 years ago
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A 26.5-g object moving to the right at 20.5 cm/s overtakes and collides elastically with a 12.5-g object moving in the same dire
Dahasolnce [82]

Answer:

v₁ =0.19 m/s and v₂ = 0.18 m/s

Explanation:

By conservation of energy and conservation of momentum we can find the velocity of each object after the collision:

<u>Momentum:</u>

Before (b) = After (a)

m_{1}v_{1b} + m_{2}v_{2b} = m_{1}v_{1a} + m_{2}v_{2a}

26.5 kg*0.205 m/s + 12.5 kg*0.150 m/s = 26.5 kg*v_{1a} + 12.5 kg*v_{2a} 7.31 kg*m/s = 26.5 kg*v_{1a} + 12.5 kg*v_{2a}     (1)      

<u>Energy:</u>

Before (b) = After (a)                        

\frac{1}{2}m_{1}v_{1b}^{2} + \frac{1}{2}m_{2}v_{2b}^{2} = \frac{1}{2}m_{1}v_{1a}^{2} + \frac{1}{2}m_{2}v_{2a}^{2}          

26.5 kg*(0.205 m/s)^{2} + 12.5 kg*(0.150 m/s)^{2} = 26.5 kg*v_{1a}^{2} + 12.5 kg*v_{2a}^{2}              

1.40 J = 26.5 kg*v_{1a}^{2} + 12.5 kg*v_{2a}^{2}   (2)    

<u>From equation (1) we have:</u>

v_{2a} = \frac{7.31 kg*m/s - 26.5 kg*v_{1a}}{12.5 kg}   (3)

<u>Now, by entering equation (3) into (2) we have: </u>  

1.40 J = 26.5 kg*v_{1a}^{2} + 12.5 kg*(\frac{7.31 kg*m/s - 26.5 kg*v_{1a}}{12.5 kg})^{2}    (4)

By solving equation (4) for v_{1a}, we will have two values for

v_{1a} = 0.16                        

v_{1a} = 0.21  

We will take the average of both values:

v_{1a} = 0.19 m/s

Now, by introducing this value into equation (3) we can find v_{2a}:

v_{2a} = \frac{7.31 kg*m/s - 26.5 kg*0.19 m/s}{12.5 kg}

v_{2a} = 0.18 m/s

Therefore, the velocity of object 1 and object 2 after the collision is 0.19 m/s and 0.18 m/s, respectively.

I hope it helps you!    

6 0
3 years ago
Which coordinates best estimates the location of Woonsocket, RI?
STatiana [176]

Answer:

\43 ° n, 72 ° w

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5 0
3 years ago
How long would it take for a penny to fall from the top of the empire state building? the building is 381 meters tall.
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Here, S = ut + 1/2 at²
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In short, Your Answer would be 8.82 s

Hope this helps!
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On the contrary, mechanical waves are caused by the 'wave amplitude'. Mechanical wave can travel in solid, liquid and gas and are considered to be periodic disturbance.

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2 years ago
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