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irina1246 [14]
4 years ago
8

How long can the body maintain an anaerobic burst of energy

Physics
1 answer:
Veseljchak [2.6K]4 years ago
5 0
The body can maintain anaerobic burst energy takes thirty seconds to around two minutes.
We have aerobic energy and anaerobic energy. Aerobic energy is used when there is a lot of intake of oxygen into the body. While anaerobic lacks oxygen to the body for example short sprint.
Aerobic respiration is being utilized in the body whenever oxygen cannot be delivered to the muscle when contraction in needed.
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Assume it takes 10 J to stretch a spring 10 cm beyond its natural length. Find the work required (in Joules) to stretch the spri
Lady bird [3.3K]

Answer:

W = 30 J

Explanation:

given,

Work done = 10 J

Stretch of spring, x = 0.1 m

We know,

dW = F .dx

we know, F = k x

\int dW = \int_0^{0.1} k.x dx

W = \int_0^{0.1} k.x dx

W = k[\dfrac{x^2}{2}]_0^{0.1}

10 = k\dfrac{0.1^2}{2}

k = 2000

now, calculating Work done by the spring when it stretched to 0.2 m from 0.1 m.

W = \int_{0.1}^{0.2} 2000 x dx

W = 2000 [\dfrac{x^2}{2}]_{0.1}^{0.2} dx

W = 1000 x 0.03

W = 30 J

Hence, work done is equal to 30 J.

4 0
3 years ago
In which scenarios does conduction occur? Check all that apply.
Lera25 [3.4K]
2,3,5 are correct just took the test
4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!
Gwar [14]
The third one.

The nucleus of an atom is made up of protons and neutrons. Protons and neutrons have the same relative mass (rounded to 1). Electrons have an extremely small mass.

Therefore, the particles in the nucleus are more massive than those in the electron cloud.
4 0
2 years ago
A 1kg cart slams into a stationary 1kg cart at 2 m/s. The carts stick together and move forward at a speed of 1 m/sl. Determine
finlep [7]

Answer:

No, it is not conserved

Explanation:

Let's calculate the total kinetic energy before the collision and compare it with the total kinetic energy after the collision.

The total kinetic energy before the collision is:

K_i = K_1 + K_2 = \frac{1}{2}mv_1^2 + \frac{1}{2}mv_2^2=\frac{1}{2}(1 kg)(2 m/s)^2+\frac{1}{2}(1 kg)(0)^2=2 J

where m1 = m2 = 1 kg are the masses of the two carts, v1=2 m/s is the speed of the first cart, and where v2=0 is the speed of the second cart, which is zero because it is stationary.

After the collision, the two carts stick together with same speed v=1 m/s; their total kinetic energy is

K_f = \frac{1}{2}(m_1+m_2)v^2=\frac{1}{2}(1 kg+1kg)(1 m/s)^2=1 J

So, we see that the kinetic energy was not conserved, because the initial kinetic energy was 2 J while the final kinetic energy is 1 J. This means that this is an inelastic collision, in which only the total momentum is conserved. This loss of kinetic energy does not violate the law of conservation of energy: in fact, the energy lost has simply been converted into another form of energy, such as heat, during the collision.

3 0
4 years ago
You can use one or more of your five senses to make ______ during an inquiry activity
FromTheMoon [43]
<span>You can use one or more of your five senses to make observations during an inquiry activity.
we have nervous system which has special sensory system, we have sensory organs and senses, the five senses are touch, smell, hearing, sight and taste. every sense is related to an organ, like we can touch with hands, hear with ears, sight is related to eyes, we can smell with nose and taste with tongue.

</span>
7 0
3 years ago
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