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JulsSmile [24]
3 years ago
12

Can some explain me how to find the answers

Mathematics
2 answers:
Elanso [62]3 years ago
4 0
(a) r = the weight of Rajesh's package and m = the weight of Mohib's package:

r = 2m + 3
r + m = 15

(b) The easiest way to solve this equation would be to use substitution.  The first equation says that r is equal to "2m + 3", so we can plug 2m + 3 in for the r in the second equation, and then solve for m:

r+m=15\(2m+3)+m=15\3m+3=15\3m=12\m=4

Now that we have m, we can plug it into one of the equations to find r:

r=2m+3\r=2(4)+3\r=8+3\r=11

So, the weight of Rajesh's package is 11 pounds, and the weight of Mohib's package is 4 pounds.  This makes sense because both of these add up to 15 and Rajesh's package is three more than two times the weight of Mohib's package, as described in the question.

(c) Mohib's graph is the correct graph because it intersects at the correct point (4 on the Mohib axis and 11 on the Rajesh axis).  The other graph shows the intersection of the two lines at the wrong point, giving the wrong weights of the two packages.
Svetlanka [38]3 years ago
4 0
What textbook and pg # is this? I wanna be able to practice
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Can someone please help I can't solve this problem!!!!!!!!!!!
notsponge [240]

Answer:

8 dolls

Step-by-step explanation:

METHOD 1:

Step 1: Convert 25% into decimal (0.25)

Step 2: Multiply by 32 (32 × 0.25 = 8)

METHOD 2:

25% of a number will be one-fourth of that number. Divide 32 by 4 to get 8 (or multiply 32 by 1/4).

6 0
2 years ago
What is the slope of the line? y + 5=2(x+1)
mel-nik [20]

Answer:

2

Step-by-step explanation:

So we have the equation:

y+5=2(x+1)

This is in the format point-slope form, where:

y-y_1=m(x-x_1)

Here, m is the slope.

In our original equation, 2 replaces m.

Therefore, our slope is 2.

5 0
3 years ago
Read 2 more answers
Let X denote the data transfer time (ms) in a grid computing system (the time required for data transfer) between a "worker" com
My name is Ann [436]

Answer:

a. The value of alpha is 3.014 and the value of beta is 12.442

b. The probability that data transfer time exceeds 50ms is 0.238

c. The probability that data transfer time is between 50 and 75 ms is 0.176

Step-by-step explanation:

a. According to the given data we have that the mean and standard deviation of the random variable X are 37.5 ms and 21.6.

Therefore, E(X)=37.5 and V(X)=(21.6)∧2  

To calculate alpha we would have to use the following formula:

alpha=E(X)∧2/V(X)

alpha=(37.5)∧2/21.6∧2

alpha=1,406.25 /466.56

​alpha=3.014

To calculate beta we would have to use the following formula:

β=  V(X) ∧2/E(X)

β=(21.6)  ∧2/37.5

β=466.56 /37.5

β=12.442

b. E(X)=37.5 and V(X)=(21.6)∧2  

Therefore, P(X>50)=1−P(X≤50)

Hence, To calculate the probability that data transfer time exceeds 50ms we use the following formula:

P(X>50)=1−P(X≤50)

=1−0.762

=0.238

The probability that data transfer time exceeds 50ms is 0.238

c. E(X)=37.5 and V(X)=(21.6)∧2  

​Therefore, P(50<X<75)=P(X<75)−P(X<50)  

Hence, To calculate the probability that data transfer time is between 50 and 75 ms we use the following formula:

P(50<X<75)=P(X<75)−P(X<50)

=0.938−0.762

=0.176

​

The probability that data transfer time is between 50 and 75 ms is 0.176

6 0
3 years ago
Find the product:<br><br> (5/3)(2/3)(2/1)
vampirchik [111]

Answer:

20/9

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
What is the best estimate for 59.87 - 42.1? A. 18 B. 22 C. 25 D. 30
Sedaia [141]

Answer:

do you still need help on tge questio ?

3 0
3 years ago
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