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IceJOKER [234]
3 years ago
10

Two cards are chosen at random without replacement from a well-shuffled pack. what is the probability that the second card drawn

is also a king given that the first one drawn was a king?
Mathematics
1 answer:
frosja888 [35]3 years ago
4 0
Having drawn one king, there are 3 kings remaining and a total of 51 cards. Therefore the probability of drawing another king is 3/51 = 1/17.
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Please help!! This is so confusing! 100 points!!
masya89 [10]

Answer:

The value of the expression given is:

  • 4

Step-by-step explanation:

First, you must divide the expression in three, and to the final, you can multiply it:

  1. [(3^8)*(2^(-5))*(9^0)]^(-2)
  2. [(2^(-2))/(3^3)]^4
  3. 3^28

Now, we can solve each part one by one:

<em>First part. </em>

  • 3^8 = 6561
  • 2^(-5) = 0.03125
  • 9^0 = 1 (Whatever number elevated to 0, its value is 1)
  • (6561 * 0,03125 * 1) = 205.03125

And we elevate this to -2:

  • 205.03125^-2 = 2<u>.378810688*10^(-5)</u> or <u>0.00002378810688 </u>

<em>Second part. </em>

  • 2^(-2) = 0.25
  • 3^3 = 27
  • 0.25 / 27 = 9.259259259 * 10^(-3) or 0.00925925925925

And we elevate this to 4:

  • 0.00925925925925^4 = <u>7.350298528 * 10^(-9)</u> or <u>0.000000007350298528 </u>

<em>Third Part. </em>

  • 3^28 = <u>2.287679245 * 10^13</u> or <u>22876792450000</u>

At last, we multiply all the results obtained:

  • 0.00002378810688 * 0.000000007350298528 * 22876792450000 = <u>3.999999999999999999</u> approximately <u>4</u>

<u><em>We approximate the value because the difference to 4 is minimal, which could be obtained if we use all the decimals in each result</em></u>.

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Answer: 9\pi\ in.

Step-by-step explanation:

Given

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So, the radius is r=\frac{d}{2}=4.5\ in.

The circumference is given by 2\pi r

Insert the values

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Thus, the circumference of the circle is 9\pi\ in.  

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galina1969 [7]

Answer:

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Step-by-step explanation:


7 0
3 years ago
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X = 6

11-3x=-7
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Answer:

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