Ask question

Ask question

All categories

2 years ago

10

Two cards are chosen at random without replacement from a well-shuffled pack. what is the probability that the second card drawn

is also a king given that the first one drawn was a king?

1 answer:

frosja888 [35]2 years ago

4 0

Having drawn one king, there are 3 kings remaining and a total of 51 cards. Therefore the probability of drawing another king is 3/51 = 1/17.

You might be interested in

What is the value of the expression 2 over 3 subtracted by 5 over 6 divided by 3 over 4

Tju [1.3M]

I did the problem and I got negative 4 over 9

5 0

3 years ago

Read 2 more answers

Evaluate the expression for the given value of the variable(s).

Lesechka [4]

The answer to what you have there is -55 using order of operations. 5 times -6 is -30. 5 times -5 is -25. add. You get -55.

3 0

2 years ago

Read 2 more answers

Helpppp meee plsssss

Sholpan [36]

Answer:

B

Step-by-step explanation:

1/6x+ 4/6x = -4/6

5/6x= -4/6

x=( -4/6)/ (-5/6)

x= 4/5

8 0

2 years ago

spin [16.1K]

Answer:

AAS

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

NEED ASAP CORRECT ANSWER GETS BRAINLIESt

andriy [413]

Answer:

QS = 8x - 2

Step-by-step explanation:

QS = QR + RS

QS = 6x - 11 + 2x + 9

QS = 8x - 2

8 0

2 years ago