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kirill [66]
3 years ago
10

Help me ASAP PLZZZZZ

Mathematics
1 answer:
jarptica [38.1K]3 years ago
5 0

Answer:

what question do u need help with???


Step-by-step explanation:


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You can use the formula is A = b.h to find the area of every triangle.
Julli [10]

Answer:

False.

Step-by-step explanation:

The area = 1/2.b.h.

4 0
3 years ago
Read 2 more answers
Please Help! (no rush)
Anon25 [30]

Answer:

The answer to your question is below

Step-by-step explanation:

Formula  an expression that uses variables to state a rule

Constant   a number; a term containing no variables

Variable  a letter or symbol used to represent an unknown number

Term   a number or a variable, or the product of a number and variable(s)

Expression   one term or multiple terms connected by an addition or subtraction sign

3 0
4 years ago
Read 2 more answers
The value -2 is a lower bound for the zeros of the function shown below.
Juliette [100K]

Answer:

  a) true

Step-by-step explanation:

The bottom-line numbers from synthetic division <em>alternate signs</em>, indicating that -2 is a lower bound. The given statement is true.

__

If the signs were all positive, it would indicate the proposed zero is an <em>upper bound</em>.

__

A graph shows all real zeros are greater than -2.

4 0
4 years ago
BC = 6, EF = 12 Based on the given information, choose the similarity statement that you would use to say ABC~DEF. If you could
vovangra [49]

Answer:

The answer is "NOT"

Step-by-step explanation:

  • To demonstrate a similar statement we want to have yet another side or some other angle, however, the third section is not proportional.  
  • Its sides were equivalent in proportions (yeah sure they are) + corner by the by is not given.
  • There is no triangle angle provided so, that we can not enforce the SAS argument.  
  • It is not evidence of similarity between ABC ≈DEF.
6 0
3 years ago
Prime numbers problem :)
Hatshy [7]

Answer:

The answer to your question is (2)(3)(11)

Step-by-step explanation:

Data

154

Process

1.- Find the prime factors of 154, starting with 2, then, 3, 5, 7, etc

                    154  2

                       77  7

                       11   11

                        1

2.- Write 154 as a composition of prime factors

                    154 = (2)(7)(11)

3.- Conclusion

The prime factors of 154 are 2, 3 and 11

7 0
3 years ago
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