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g100num [7]
3 years ago
10

D = b^2 -4ac solve for a 2/3 (x-18y) = 6y solve for x

Mathematics
1 answer:
seropon [69]3 years ago
7 0

Answer:

a = \frac{b^2-d}{4c}

x = 27y

Step-by-step explanation:

Order of Operations: BPEMDAS

<u>Question 1</u>

Step 1: Write out discriminant

d = b² - 4ac

Step 2: Subtract b² on both sides

d - b² = -4ac

Step 3: Divide both sides by -1

b² - d = 4ac

Step 4: Divide both sides by 4c

a = \frac{b^2-d}{4c}

<u>Question 2</u>

Step 1: Write out equation

2/3(x - 18y) = 6y

Step 2: Distribute parenthesis

2/3x - 12y = 6y

Step 3: Isolate <em>x </em>by adding 12y on both sides

2/3x = 18y

Step 4: Divide both sides by 2/3

x = 27y

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4 years ago
Given that sine of theta = 21/29, what is the value of cosine of theta, for 0° &lt; theta &lt; 90°?
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If the value of θ is 46.4°. Then the value of the cosine of θ will be 20/29.

<h3>What is trigonometry?</h3>

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The value of sine of θ is 21/29.

Then the value of θ will be

sin θ = 21/29

     θ = sin⁻¹(21 / 29)

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Then the value of the cosine of θ will be

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More about the trigonometry link is given below.

brainly.com/question/22698523

#SPJ1

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