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2 years ago

D = b^2 -4ac solve for a 2/3 (x-18y) = 6y solve for x

Mathematics

1 answer:

seropon [69]2 years ago

7 0

Answer:

a = $\frac{b^2-d}{4c}$

x = 27y

Step-by-step explanation:

Order of Operations: BPEMDAS

Question 1

Step 1: Write out discriminant

d = b² - 4ac

Step 2: Subtract b² on both sides

d - b² = -4ac

Step 3: Divide both sides by -1

b² - d = 4ac

Step 4: Divide both sides by 4c

a = $\frac{b^2-d}{4c}$

Question 2

Step 1: Write out equation

2/3(x - 18y) = 6y

Step 2: Distribute parenthesis

2/3x - 12y = 6y

Step 3: Isolate x by adding 12y on both sides

2/3x = 18y

Step 4: Divide both sides by 2/3

x = 27y

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Can someone solve these math problems pls

NNADVOKAT [17]

Answer:

A yes

B no

C yes

D yes

Step-by-step explanation:

sorry I don't know how to do the other one

5 0

2 years ago

Is (5,6.5) a solution to y= -1/2x + 9?

Jlenok [28]

6.5 = - 1/2(5) + 9

6.5 = - 2.5 + 9 which is the same as 6.5 = 9 - 2.5

6.5 = 6.5

So yes, this ordered pair IS a solution.

3 0

3 years ago

Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x + 2) f(x) = (x – 2)(x + 2) f(x) = (x + 1)(x – 2)

strojnjashka [21]

we know that

If the vertex is on the y-axis, then the x-coordinate of the vertex is equal to zero

we are going to verify the vertex of each one of the functions to determine the solution

Remember that

The equation in vertex form of a vertical parabola is equal to

$y=a(x-h)^{2} +k$

where

(h,k) is the vertex

if $a>0$ -------> the parabola open upward (vertex is a minimum)

if $a$ -------> the parabola open downward (vertex is a maximun)

case A) $f(x)=(x-2)^{2}$

This is a vertical parabola open upward

the vertex is the point $(2,0)$

therefore

The function $f(x)=(x-2)^{2}$ does not have a vertex on the y-axis

case B) $f(x)=x(x+2)$

$f(x)=x(x+2)=x^{2}+2x$

convert to vertex form

Complete the square. Remember to balance the equation by adding the same constants to each side.

$f(x)+1=x^{2}+2x+1$

Rewrite as perfect squares

$f(x)+1=(x+1)^{2}$

$f(x)=(x+1)^{2}-1$

the vertex is the point $(-1,-1)$

therefore

The function $f(x)=x(x+2)$ does not have a vertex on the y-axis

case C) $f(x)=(x-2)(x+2)$

$f(x)=(x-2)(x+2)=x^{2}-2^{2}$

$f(x)=x^{2}-4$

the vertex is the point $(0,-4)$

The x-coordinate of the vertex is equal to zero

therefore

The function $f(x)=(x-2)(x+2)$ has a vertex on the y-axis

case D) $f(x)=(x+1)(x-2)$

$f(x)=(x+1)(x-2)\\ \\f(x)= x^{2}-2x+x-2 \\ \\f(x)= x^{2} -x-2$

convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+2= x^{2} -x$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$f(x)+2+0.25= x^{2} -x+0.25$

$f(x)+2.25= x^{2} -x+0.25$

Rewrite as perfect squares

$f(x)+2.25= (x-0.50)^{2}$

$f(x)=(x-0.50)^{2}-2.25$

the vertex is the point $(0.5,-2.25)$

therefore

The function $f(x)=(x+1)(x-2)$ does not have a vertex on the y-axis

the answer is

$f(x)=(x-2)(x+2)$

6 0

3 years ago

Read 2 more answers

Answer with steps thnx

expeople1 [14]

Answer:

The area is 432cm squared.

Step-by-step explanation:

To find the area, first you split the figure into 2 rectangles.

The rectangle facing up would be 8cm by 30cm, and the rectangle pointing to the left would be 8cm by 24cm (because you subtract 8 by 32). Next, with those numbers, you can easily find the area. 8cm x 30cm equals to 240cm squared, and 8cm x 24cm equals to 192cm squared. Lastly, you add the both of the areas together, 240cm and 192cm, and you get 432cm squared.

6 0

3 years ago

How many times larger is the value of 170 000 than 170?

Mashcka [7]

The value 170 000 is 100x larger than the value 170.

8 0

3 years ago

Read 2 more answers