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Alexandra [31]
3 years ago
14

The double number line shows that 444 bottles of water cost 101010 dollars at a music festival. Based on the ratio shown in the

double number line, how much does 333 bottles of water cost?

Mathematics
2 answers:
statuscvo [17]3 years ago
7 0

Answer:

Please see the attachment for double number line.

Explanation:

We are given cost of 4 water bottles is $10

We can write ,

Cost of 4 bottles = $10

Cost of 1 bottle = $2.5

Cost of 2 bottles =$5

Cost of 3 bottles =  = $7.5

Cost of n bottles = $2.5n

Now we draw the double number line.

Bottom line(Line 1)  will take as number of bottles:  

1   2   3   4   5   6  

Above line (Line 2) will show the cost of corresponding number of bottles:

2.5  5  7.5  10  12.5  15  

Read more on Brainly.com - brainly.com/question/11566849#readmore

Step-by-step explanation:

MrRissso [65]3 years ago
4 0

Answer:

Please see the attachment for double number line.

Explanation:

We are given cost of 4 water bottles is $10

We can write ,

Cost of 4 bottles = $10

Cost of 1 bottle = $2.5

Cost of 2 bottles =$5

Cost of 3 bottles = 3\times 2.5 = $7.5

Cost of n bottles = $2.5n

Now we draw the double number line.

Bottom line(Line 1)  will take as number of bottles:  

1   2   3   4   5   6  

Above line (Line 2) will show the cost of corresponding number of bottles:

2.5  5  7.5  10  12.5  15  


 


wassupyeetkid
2 years ago
?
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3 0
2 years ago
I need help.. 
Debora [2.8K]
This is exactly like the one with the 'n's that you posted yesterday.
I guess you didn't get enough help on that one to understand it.

<span><u>7k/8 - 3/4 - 5k/16 = 3/8</u>

3/4 is the same as 6/8.
Add it to each side of the equation:

7k/8         - 5k/16 = 9/8

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From this point, you can proceed directly to the numerical value of 'k'
if you need it.<u />

In your question, you said you need help, and I showed you how to
strip the problem down so that the only thing left is ' k = something '.
Giving you the answer is no help.  Nobody actually needs the answer.
</span>


8 0
3 years ago
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