Funtion ! in vertex form is given by
<span>f(x) = 4x^2 + 8x + 1</span> = 4(x^2 + 2x + 1/4) = 4(x^2 + 2x + 1 + 1/4 - 1) = 4(x + 1)^2 + 4(-3/4) = 4(x + 1)^2 - 3
Thus, the least minimun value is (-1, -3)
Also, the least minimum value of function 2 is (-1, 0)
Therefore, function 1 has the least minimum value at (-1, -3)
Answer:
Hello !
The solutions are: -8 , -4 , 6
Hope this helps !
Answer:
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Step-by-step explanation:
The radius of the circle is 1.
Answer:

Step-by-step explanation:
Given
Geometry Progression


Required
Calculate the second term
First, we need to write out the formula to calculate the nth term of a GP

For first term: Tn = 500 and n = 1




For fought term: Tn = 32 and n = 4


Substitute 500 for a

Make r^3 the subject


Take cube roots
![\sqrt[3]{r^3} = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Br%5E3%7D%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)
![r = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=r%20%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)

Using: 
and 




<em>Hence, the second term is 200</em>