The bottom right graph is correct. x must fall between 3 and 6, so that automatically rules out the bottom left, as one of the points falls on 2.
the top left is incorrect because it doesn't show that x is greater than or EQUAL to three. it has an open circle rather than a closed circle. that's two answer choices eliminated.
from there, you just have to refer back to your given information:
<span>3≤x≤6
the given info says that x must be between or equal to 3 and 6. the top right graph leaves out a "step" because it has 5 and 6 as solid dots side by side.</span>
QUESTION 5
The side length of the first tra-pezoid and the second tra-pezoid are in the ratio
.
To find the corresponding ratio of their area, we square each term in the ratio.
The ratio of the area of the first figure, to the ratio of the area of the second is
![5^2:7^2=25:49](https://tex.z-dn.net/?f=5%5E2%3A7%5E2%3D25%3A49)
QUESTION 6
The side length of the first figure and the second figure are in the ratio
.
To find the corresponding ratio of their area, we square each term in the ratio.
The ratio of the area of the first figure, to the ratio of the area of the second figure is
![12^2:7^2=144:49](https://tex.z-dn.net/?f=12%5E2%3A7%5E2%3D144%3A49)
QUESTION 7
Let
represent the height of this triangle.
![\sin 30\degree=\frac{h}{6}](https://tex.z-dn.net/?f=%5Csin%2030%5Cdegree%3D%5Cfrac%7Bh%7D%7B6%7D)
This implies that;
![h=6\sin 30\degree](https://tex.z-dn.net/?f=h%3D6%5Csin%2030%5Cdegree)
![h=3ft](https://tex.z-dn.net/?f=h%3D3ft)
The area of the triangle is ![=\frac{1}{2}bh](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7Dbh)
The base is 9 ft and the height is 3 ft.
We substitute these values to obtain;
![A=\frac{1}{2}(9)(3)](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%289%29%283%29)
to the nearest tenth.
QUESTION 8
The area of a parallelogram is ![base\times\:height](https://tex.z-dn.net/?f=base%5Ctimes%5C%3Aheight)
Let h represent the height of this parallelogram.
![\sin60\degree=\frac{h}{6}](https://tex.z-dn.net/?f=%5Csin60%5Cdegree%3D%5Cfrac%7Bh%7D%7B6%7D)
![h=6\sin60\degree](https://tex.z-dn.net/?f=h%3D6%5Csin60%5Cdegree)
![h=3\sqrt{3}m](https://tex.z-dn.net/?f=h%3D3%5Csqrt%7B3%7Dm)
The area of the parallelogram is ![=10\times3\sqrt{3}m^2](https://tex.z-dn.net/?f=%3D10%5Ctimes3%5Csqrt%7B3%7Dm%5E2)
![=30\sqrt{3}m^2](https://tex.z-dn.net/?f=%3D30%5Csqrt%7B3%7Dm%5E2)
to the nearest tenth.
Answer: x = 2.65, y = 3.81
Step-by-step explanation:
ABC similar to PQR
1) Find the ratio of corresponding sides
2) Use that ratio to find values for x & y
1) Side AB = 2.76cm & Side PR = <em>y</em><em> </em>cm
Side BC = <em>x</em> cm & Side RQ = 3.66 cm
Side CA = 3 cm & Side QP = 4.14 cm (both lengths given)
Can match 3 to 4.14 & ratio of sides in ABC to PQR= 3 /4.14
Length of sides ABC = 3/4.14 times the length of sides PQR
2) x = (3 / 4.14) * 3.66 = 2.65
Now solve for y, ABC to PQR: 2.76 = (3 / 4.14) (<em>y </em>)
<em>equality property</em> (both sides) & inverse operation to isolate <em>y : </em> . 2.76 ÷ (3 / 4.14) = (3 / 4.14 ) ÷ (3 / 4.14) (<em>y</em><em>)</em>
2.76 * (4.14 / 3) = 3 / 4.14 * (4.14 / 3) (<em>y</em><em>)</em>
(2.76 * 1.38 ) = 3.81 = <em>y</em>
<em></em>
<em>Scale Factor Method: Determine the Multiplier</em>
Small to Big or Big to Small ➜ Be sure not to switch
Answer:
700
Step-by-step explanation:
(49 x 100) / 7
Using the Empirical Rule, it is found that the standard deviation of the sample is of:
C. 4
By the <em>Empirical Rule</em>, 95% of the measures are within 2 standard deviations of the mean, that is, between 2 standard deviations below the mean and 2 standard deviations above the mean.
95% of people's heights are <u>between 168 and 184 centimeters</u>, hence, there are 4 standard deviations between 168 and 184 centimeters. Then:
![4s = 184 - 168](https://tex.z-dn.net/?f=4s%20%3D%20184%20-%20168)
![4s = 16](https://tex.z-dn.net/?f=4s%20%3D%2016)
![s = \frac{16}{4}](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7B16%7D%7B4%7D)
![s = 4](https://tex.z-dn.net/?f=s%20%3D%204)
Hence, option C is correct.
A similar problem is given at brainly.com/question/25807482