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algol [13]
3 years ago
5

Being 360 meters apart, two dogs started running towards each other at the same time. In 20 seconds the distance between them wa

s 200 meters. How fast each of them ran if one of them ran faster by 3 meters per second?

Mathematics
2 answers:
lubasha [3.4K]3 years ago
7 0
One dog goes at 2.5 meters per second. The other one goes at 5.5 meters per second.

Thepotemich [5.8K]3 years ago
7 0

Answer:

Speed of one dog = 2.5m/s and speed of other dog = 5.5 m/s

Step-by-step explanation:

Formula: speed = distance/time

It is given that,

Being 360 meters apart, two dogs started running towards each other at the same time. In 20 seconds the distance between them was 200 meters. And one of them ran faster by 3 meters per second

<u>To find speed</u>

Let x be the speed of one dog and speed of 2nd dog = x + 3

After 20 seconds they travel = 360 - 200  = 160 meters.

let d be the distance traveled by 1st dog

distance traveled by 2nd dog = 160 - d

In the case of first dog we can write

speed = distance/time

x = d/20

20x = d  -----(1)

In the case of 2nd dog,

(x + 3) = (160 - d)/20

20x + 60 = 160 - d     ----(2)

Substitute value of 20x = d

(2) ⇒ d + 60 = 160 -d

2d = 160 - 60 = 100

d = 50

Distance covered by 1st dog = 50.

x =50/20 = 2.5 m/s

Speed of 1st dog = 2.5m/s

speed of 2nd dog 2.5 + 3 = 5.5 m/s

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