I believe
1.b
2.c
3.b
4.d
5.a
6.b
7.b
8.c
9.d
10.b
Answer:
(a) 1/2; (b) no
Explanation:
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.
In contrast to this, her husband is diseased so his genotype will be XᵇY.
The Punnett square diagram related to the cross is attached.
(a) Proportion of their sons expected to be G6PD is 1/2:
They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.
(b) If the husband were G6PD deficient, the answer will not change.
The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.
Answer: i also need this so please anyone
Explanation:
The recombinant offsprings are normally the offsprings containing a combination of the parents allele, result in a genotype that differs from both parents genotype. The phenotype May be different as well although it is likely that the phenotype could be the same as the parents, as seen in the case of heterozygous dominant having the same phenotype as homozygous dominant.
Answer:
3. CABD
Explanation:
The gene mapping refers to providing position to the genes on the chromosomes. The first gene map was constructed by the Alfred Sturtevant on the basis of recombinant produces or recombination frequency which was calculated.
The gene mapping refers to providing position to the genes on the chromosomes.
In the given question to construct gene map:
1. Look for the highest recombination frequency that is 50% between the C and D.
2. Now look for second-highest value and place the gene accordingly.
3.Similarly, place the genes in the decreasing order of recombination frequency and this will result that the sequence of the genes is- CABD.
Thus, Option-3 is correct.