5 + 10 + 12 = 27 scores are less than 3
Answer:
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by

In which r is the number of failures we want and p is the probability of a failure.
In this problem, we have that:
r = 1 because we want the first failed unit.
![p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5](https://tex.z-dn.net/?f=p%20%3D%200.4%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3ESo%3C%2Fp%3E%3Cp%3E%5Btex%5DE%20%3D%20%5Cfrac%7Br%7D%7Bp%7D%20%3D%20%5Cfrac%7B1%7D%7B0.4%7D%20%3D%202.5)
The expected number of systems inspected until the first failed unit is 2.5
Answer:
232.5
Step-by-step explanation:
If you take 15.50 and multiply it by 15 you get 232.5 if its wrong my apologies
Answer:
320
Step-by-step explanation:
4*80=320
Answer:
<em>Answer is </em><em>10</em><em>/</em><em>7</em>
Step-by-step explanation:
[tex] (\frac{6}{10} )r = \frac{6}{7} \\ cancelling \: 6 \: on \: both \: sides \\ (\frac{1}{10} )r = \frac{1}{7} \\ \frac{r}{10} = \frac{1}{7} \\ r = \frac{10}{7} \: \\
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