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3 years ago

Please answer this in two minutes

Mathematics

1 answer:

alexandr1967 [171]3 years ago

3 0

Answer:

u = $\sqrt{6}$ .

Step-by-step explanation:

This is a 45-45-90 triangle.

That means that there are two side lengths with lengths of x, and a hypotenuse with a length of xsqrt(2). We can then set up a proportion.

$\frac{1}{\sqrt{3} } =\frac{\sqrt{2} }{u}$

1 * u = $\sqrt{3} * \sqrt{2}$

u = $\sqrt{6}$ .

Hope this helps!

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Write a rule for the nth term of the arithmetic sequence. Then graph the first six terms of the sequence. a6=-12 a12=-36

denis-greek [22]

Answer:

We need to find the first term. We can use the formula

an = a1 + d(n - 1)

to solve for a1. We already know the 12th term, a12, common difference, d, and nth sequence, n.

a12 = -36

d = -4

n = 12

-36 = a1 - 4(12 - 1)

-36 = a1 - 44

8 = a1

The first term is 8. Therefore, your formula is

an = 8 - 4(n - 1)

an = -4n + 12

Then use this formula to graph.

n is the independent variable.

an is the dependent variable.

Your graph will be a line.

n | an

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1 8

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Step-by-step explanation:

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3 years ago

WHICH IS NOT A LINEAR FUNCTION

Tom [10]

Answer:

OPTION C

Step-by-step explanation:

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2 years ago

Determine the zeroes of the polynomial

Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

$(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)} \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)} -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\$

$\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}$

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3 years ago

Which graph represents the inequality y>1-3x

slava [35]

Answer:

b............ .......... which one is a b c d

For this case we must indicate the graph of the following inequality:

y≥1−3x

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We test option A, we substitute the point (0,0) in the inequality, if it is fulfilled then the graph corresponds to it.

It is not fulfilled

We test the last option B, we choose the point (3,1) that belongs to the graph:

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2 years ago

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fiasKO [112]

Answer:

4/3

Step-by-step explanation:

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