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3 years ago

Complete the following definition.

Mathematics

1 answer:

vova2212 [387]3 years ago

8 0

Answer:

A. p < r < q and p < s < q

Step-by-step explanation:

Any pair of irrational numbers will have both a rational number and an irrational number between them. (Actually, this is true for any two distinct numbers of any kind.)

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A two digit number is written at random what is the probability that the number will be odd

leonid [27]

Answer:

50%

Step-by-step explanation:

So there are 90 2 digit numbers. There are 45 2 digit odd numbers.

The probability should be 50%

7 0

3 years ago

Landon is building new bookshelves for his bookstore's new mystery section. Each shelf can hold 34 books. There are 1,265 myster

Alborosie

Answer:

37.2 = 38

Step-by-step explanation:

After divideing 1265 by 34, you will get 37.2. As you cannot have books not in bookshelves, you will have to round up and have 38 bookshelves.

3 0

3 years ago

Determine whether y varies directly with x. If so, find the constant of variation k.

musickatia [10]

The answer is the option D because the formula is y upon x

3 0

4 years ago

Solve the equation for x in terms of c

Dovator [93]

$solve\:for\:x,\:\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}=\frac{5}{2}$

$\mathrm{Add\:}\frac{1}{4}\mathrm{\:to\:both\:sides}$

$\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}+\frac{1}{4}=\frac{5}{2}+\frac{1}{4}$

$\frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11}{4}$

$\mathrm{Multiply\:both\:sides\:by\:}3$

$3\cdot \frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11\cdot \:3}{4}$

$2cx+1=\frac{33}{4}$

$\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}$

$2cx+1-1=\frac{33}{4}-1$

$2cx=\frac{29}{4}$

$\mathrm{Divide\:both\:sides\:by\:}2c$

$x=\frac{29}{8c}$

<h3>Therefore, correct option is C. option.</h3><h3>C. x=29/8c</h3>

8 0

3 years ago

Use the figure to write the segment addition postulate, write an equation and solve for x.

Alenkinab [10]

Answer:

5. x = -1

6. x = 2

Step-by-step explanation:

5. AB = 5

BC = 2x + 6

AC = x + 10

AB + BC = AC (segment addition postulate)

5 + 2x + 6 = x + 10 (substitution)

Collect like terms

5 + 6 + 2x = x + 10

11 + 2x = x + 10

2x - x = - 11 + 10

x = -1

6. AB = 9x + 7

BC = -3x + 20

AC = 39

AB + BC = AC (segment addition postulate)

(9x + 7) + (-3x + 20) = 39 (substitution)

Solve for x

9x + 7 - 3x + 20 = 39

Collect like terms

9x - 3x + 7 + 20 = 39

6x + 27 = 39

Subtract 27 from both sides

6x + 27 - 27 = 39 - 27

6x = 12

Divided both sides by 6

6x/6 = 12/6

x = 2

4 0

3 years ago