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aliya0001 [1]
3 years ago
12

Explain why the quantum number set (3, 2, 3, -½) is not possible for an electron in an atom

Chemistry
1 answer:
Triss [41]3 years ago
7 0
Ok the ML (the 3rd number) is not legit because the ML value can only be from -L to L (the second value)
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The total pressure in a mixture of gases is equal to the partial pressures of
baherus [9]

Answer:

"The total pressure in a mixture of gases is equal to the sum of partial pressures of each gas"

Explanation:

Dalton's law of partial pressures state that, in a mixture of gases, the total pressure is equal to the sum of the partial pressure exerted by each gas of the mixture. The equation is:

Total pressure = Partial pressure Gas 1 + Partial pressure Gas 2 + .... + Partial pressure Gas n

To complete the sentence we can say:

"The total pressure in a mixture of gases is equal to the sum of partial pressures of each gas"

5 0
2 years ago
How many grams of barium chloride (BaCl2) are there in 0.187 mol?<br> 0.187 mol
igor_vitrenko [27]

Answer:

38.9 grams of BaCl_2

Explanation:

0.187 mol BaCl2 x \frac{208 g}{1 mol}

0.187 m x 208 g/m

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8 0
3 years ago
Milk of magnesia has the chemical formula Mg(OH)2. What is the mass of 3.2 moles of milk of magnesia? The molar Mass of magnesiu
GenaCL600 [577]
To calculate the mass of milk of magnesia given, we need certain data like molar mass of the compound which needs the atomic mass of the atoms in the compound. We calculate as follows:

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3 0
3 years ago
A baseball that is moving through the air has ____________ energy. <br> A. potential <br> B. kinetic
Lunna [17]

Answer:

kinetic

Explanation:

3 0
3 years ago
Find the empirical formula of the compound ribose, a simple sugar often used as a nutritional supplement. A 14.229 g sample of r
MakcuM [25]

Answer:

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Explanation:

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C = 5.692/14.229 * 100 = 40%

O = 7.582/14.229 * 100 = 53.29%

H = 0.955/14.229 * 100 = 6.71%

We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.

C = 40/12 = 3.333

O = 53.29/16 = 3.33

H = 6.71/2 = 6.71

Dividing by the smaller value which is 3.33

C = 3.33/3.33 = 1

O = 3.33/3.33= 1

H = 6.71/3.33 = 2

The empirical formula of the compound ribose is CH2O

6 0
3 years ago
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