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creativ13 [48]
3 years ago
12

11. Which of the following best explains why Co, gas is easily compressible but solid CO, (dry ice) is incompressible?​

Chemistry
1 answer:
telo118 [61]3 years ago
4 0

Answer:

The molecules of solid CO2 are much closer together than the molecules of CO2 gas.

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8 0
3 years ago
Match each property of a liquid to what it indicates about the relative strength of the intermolecular forces in that liquid.
mr_godi [17]

Answer:

Strong intermolecular forces:  an increase in viscosity of the liquid, increase in surface tension, decrease in vapor pressure, and an increase in the boiling point.

Weak intermolecular forces: a decrease in viscosity, a decrease in surface tension, an increase in vapor pressure and an increase in boiling point.

Explanation:

Intermolecular forces are forces of attraction or repulsion between neighboring molecules in a substance. These intermolecular forces inclde dispersion forces, dipole-dipole interactions, hydrogen bonding, and ion-dipole forces.

The strength of the intermolecular forces in a liquid usually affects the various properties of the liquid such as viscosity, surface tension, vapour pressure and boiling point.

Strong intermolecular forces in a liquid results in the following; an increase in viscosity of the liquid, increase in surface tension, decrease in vapor pressure, and an increase in the boiling point of the liquid.

Weak intermolecular forces in a liquid results in the following; a decrease in viscosity, a decrease in surface tension, an increase in vapor pressure and an increase in boiling point of that liquid.

4 0
4 years ago
In a chemistry laboratory, a student filled a 10.0 L container with two (2) different gases. The
alexgriva [62]

Answer:

P_N=1.33atm\\\\P_O=0.67atm

P_T=2.00 atm

Explanation:

Hello.

In this case, the first step is to compute the moles of nitrogen and oxygen given their initial P, T and V conditions via the ideal gas equation:

n_{N}=\frac{P_{N}V_{N}}{RT} =\frac{2.00atm*24.0L}{0.082\frac{atm*L}{mol*K}*273K}\\ \\n_{N}=2.144molN\\\\n_{O}=\frac{P_{O}V_{O}}{RT} =\frac{2.00atm*12.0L}{0.082\frac{atm*L}{mol*K}*273K}\\ \\n_{O}=1.072molO

After that, since the total volume now, once the mixture is formed is the addition between the initial volumes (12.0 L + 24.0 L) is 36.0 L, the partial pressure of each gas turns out:

P_N=\frac{2.144mol*0.082\frac{atm*L}{mol*K}*273K}{36.0L}\\\\P_N=1.33atm\\\\P_O=\frac{1.072mol*0.082\frac{atm*L}{mol*K}*273K}{36.0L}\\\\P_O=0.67atm

Thus, the final total pressure is:

P_T= P_N+P_O=1.33atm+0.67atm\\\\P_T=2.00 atm

Best regards.

3 0
3 years ago
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