Describe the structure of ammonium lauryl sulfate. Refer to the given diagram. Your answer should include the type of bonding, t
he elements contained, and the size and shape of the molecule. Write a short paragraph.
*diagram is a molecular diagram of ammonium lauryl sulfate
*diagram is a molecular diagram of ammonium lauryl sulfate
1 answer:
Answer:
The compound contains lauryl sulfate and ammoium ions. Lauryl sulfate contains lauric acid (in black and white) , the fatty acid formed by the covalent bonds between C-C attached to hydrogens, and sulfate ions attached to lauric acid (in red) with C-S covalent bond. Sulfer is attached to oxygen by covalent bonds. In Ammonium ions, N is surrounded by four hydrogen atoms.
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Answer:
412 g Cl₂
General Formulas and Concepts:
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 3.50 × 10²⁴ molecules Cl₂
[Solve] grams Cl₂
<u>Step 2: Identify Conversions</u>
Avogadro's Number
[PT] Molar Mass of Cl - 35.45 g/mol
Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Divide/Multiply [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
412.072 g Cl₂ ≈ 412 g Cl₂
<u>Answer:</u> The percent composition by mass of hydrogen in given compound is 6.33 %
<u>Explanation:</u>
We are given:
A chemical compound having chemical formula of
It is made up by the combination of 1 nitrogen atom, 5 hydrogen atoms, 1 carbon atom and 3 oxygen atoms
To calculate the percentage composition by mass of hydrogen in the compound, we use the equation:
Mass of compound =
Mass of hydrogen =
Putting values in above equation, we get:
Hence, the percent composition by mass of hydrogen in given compound is 6.33 %