Indirect methods like mark and recapture become a strong tool to estimate population size or density in species on which it is impossible to apply a direct methods. <em>Because of their biological and ecological characteristics, the Gypsy moth and the Green lizard populations are good examples for which mark and recapture would work well.</em>
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There are different methods to study population density. There are direct methods and indirect methods. Among these last ones, we might find the Mark-Recapture technique.
The Mark-Recapture technique assumes that
- <em>the population is closed during the sampling season, there is no mortality nor natality, </em>
- <em>marks in the individual last the whole sampling season, and they do not affect the marked individual or their behavior. </em>
- <em>marked individuals are randomly distributed in the population, and </em>
- <em>all the individuals have the same probability of being sampled.</em>
The method consists of capturing a sample of individuals belonging to the population under study. After capturing the individuals, the researcher marks and releases them again. The third step is to sample again: The researcher captures new individuals and counts how many of them are marked. These marked individuals belong to the first sample.
Indirect methods like this become a strong tool to estimate population size or density in species on which it is impossible to apply a direct method such as <em>counting individuals</em>.
For instance, if we need to estimate insects population density (<u><em>Gypsy moth population</em></u>) or reptiles population density (<u><em>Green lizard population</em></u>) because of their biological and ecological characteristics, the best way of doing it is by applying indirect methods. <em>These species characterize as small-sized, fast to escape, they can hide in small inaccessible places, they have nocturnal habits, their reproductive rate is too high, and their distribution rate is wide. </em>Among many other characteristics, their population density can not be estimated by direct methods. Mark-Recapture technique is the most suitable one.
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Yah it’s a Go phase because of the cell cycle.
Answer:
Sexual reproduction is advantageous over asexual reproduction because it reduces the rate of mutation accumulation.
Explanation:
The main advantage of sexual reproduction is that it increases the genetic variation in the species by creating new combinations of alleles.
However, asexual reproduction produces more offspring, as it is usually a quicker method of reproduction. It also does not require the organisms to socialise to mate.
Sexual reproduction does not reduce the rate of mutation, which is influenced by environmental factors as well as the genome itself.
The regression equation is:
y = 1.15 – 0.251 x₁ + 0.078 x₂ + 0.306 x₁x₂
<span>
<span>
<span>
Where,
x₁ = -0.2508
x₂ = 0.0777
x₁x₂ = 0.3058
Inserting the values,
<span>
<span>
</span></span>y = 1.15 – {0.251 × (-0.2508)} + {0.078 ×(0.0777)} + {0.306 × (0.3058)}
</span></span></span>
y = 1.15 - (- 0.0629508) + 0.0060606 + 0.935748
y = 1.15 + 0.0629508 + 0.0060606 + 0.935748
y = 1.3125862
Answer:
x₁ and x₂ are main effects (a type of tuna and type of packing liquid) that contribute significant information for the prediction of <span>y.</span>
In the SI system of units, the standard unit of acceleration is 1 metre per second squared<span> (abbreviated as m/s2). Other units include the gal (sometimes known as a galileo, in either case with symbol Gal), which equals 1 centimetre per second squared, and the g (gn), equal to 9.80665 m/s2.</span>
