Question

(y + 4)^2 – 2(y + 4) + 1

Answer 1

Answer:

y = -3 and y = -3

or y = -3 with a multiplicity of 2

Step-by-step explanation:

$(y+4)^2-2(y+4)+1$

If you want to factor this, heres what you do:

$(y+4)(y+4)-2(y+4)+1$

$y^2+8y+16-2y-8+1$

$y^2+6y+9$

Then factor:

$(y+3)(y+3)$

$(y+3)^2$

The value of y:

y + 3 = 0 and y + 3 = 0

y = -3 and y = -3

or y = -3 with a multiplicity of 2

Answer 2

Answer would b y = -3 I think that would b the correct answer