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o-na [289]
3 years ago
11

Mrs. Salinas bought 10 pounds of a mixture made of M&Ms and peanuts. M&Ms sell for $3 pound. Peanuts sell for $2 pound.

She paid $24 for the mixture. How many pounds of M&Ms did she buy? How many pounds of peanuts did she buy?
Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

Mrs. Salinas buys 4 ounces M&Ms and 6 ounces Peanuts.

Step-by-step explanation:

Given,

Total weight of the mixture = 10 pounds.

Total money Mrs. Salinas paid = $24.

We have to find out the weight of each M&Ms and peanuts.

Solution,

Let the weight of M&Ms be x.

And the weight of peanuts be y.

Since total weight of the mixture is 10 pounds.

So, we can frame it in equation as;

x+y=10\ \ \ \ \ equation\ 1

Again, Total money paid by Mrs. Salinas is the sum of weight of M&Ms multiplied by price for each ounce and weight of peanuts multiplied by price for each ounce.

So, we can frame it in equation as;

3x+2y=24\ \ \ equation\ 2

Now, multiplying equation 1 by 2, we get;

2(x+y)=10\times2\\\\2x+2y=20\ \ \ \ \ equation\ 3

Now subtract equation 3 from equation 2, we get;

(3x+2y)-(2x+2y)=24-20\\\\3x+2y-2x-2y=4\\\\x=4

On substituting the value of x in equation 1, we get;

x+y=10\\\\4+y=10\\\\y=10-4\\\\y=6

Hence Mrs. Salinas buys 4 ounces M&Ms and 6 ounces Peanuts.

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