If sin(x) 1/10 what is tangent(x)

Mathematics

1 answer:

coldgirl [10]3 years ago

5 0

Sin(x) =1/10

So Cos x is not known

Hence Tan(x) = Sin(x)/Cos(x)

= 1/10/cos(x)

so cos(x)/10

You might be interested in

A. C=22d<br> B. C= d + 22d<br> C. C= d + 22<br> D. D = 22c

Lelu [443]

Step-by-step explanation:

a. that's the best answer that suits the question per day you multiply by 22

6 0

3 years ago

GCF of 4x^2y^2, 3xy^4, and 2xy^2

allsm [11]

The greatest common factor would be xy^2 because these are the only factors that they all have in common. The second term only has 1 x, so only 1 x is part of the gcf.

The 1st and 3rd terms each have y^2 therefore making it part of the gcf as well.

5 0

3 years ago

Mary earn a 8 percent commission for the instruments equipment that she sell. if she earned 2816.00 in commission on the tuba in

KatRina [158]

The anwser is C!!!!!!!!!!!!!!!!!!!!!! ik this because i calculated it my self

3 0

3 years ago

Read 2 more answers

A tank 4/5 full needs 75 litres to fill it up.how many litres does it hold when full

Ann [662]

X - the volume of the tank

$\frac{4}{5}x+75=x \\
75=x-\frac{4}{5}x \\
75=\frac{1}{5}x \ \ \ |\times 5 \\
x=375$

The tank holds 375 liters when full.

8 0

3 years ago

Solve 5x^2 - 7x + 2 = 0 by completing the square.

Reika [66]

Answer: The correct option is (c) $\dfrac{49}{100}.$

Step-by-step explanation: We are given to solve the following quadratic equation by the method of completing the square:

$5x^2-7x+2=0~~~~~~~~~~~~~~~~~~~(i)$

Also, we are to find the constant added on both sides to form the perfect square trinomial.

We have from equation (i) that

$5x^2-7x+2=0\\\\\Rightarrow x^2-\dfrac{7}{5}x+\dfrac{2}{5}=0\\\\\\\Rightarrow x^2-2\times x\times \dfrac{7}{10}+\left(\dfrac{7}{10}\right)^2+\dfrac{2}{5}=\left(\dfrac{7}{10}\right)^2\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49}{100}-\dfrac{2}{5}\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49-40}{100}\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{9}{100}\\\\\\\Rightarrow x-\dfrac{7}{10}=\pm\dfrac{3}{10}\\\\\\\Rightarrow x=\pm\dfrac{3}{10}+\dfrac{7}{10}.$

So,

$x=\dfrac{3}{10}+\dfrac{7}{10},~~~~~~~~x=-\dfrac{3}{10}+\dfrac{7}{10}\\\\\\\Rightarrow x=\dfrac{10}{10},~~~~~~~~\Rightarrow x=\dfrac{-3+7}{10}\\\\\\\Rightarrow x=1,~-\dfrac{2}{5}.$

Thus, the required solution is $x=1,~-\dfrac{2}{5}.$ and the value of the constant added is $\dfrac{49}{100}.$

Option (c) is correct.

3 0

3 years ago