The equation of the parabola is (y-1)^2 = 16(x+3)
1 answer:
We know that
if the y terms is squared so it opens left or right
Is a Horizontal Parabola, the equation is of the form
(y-k)²=4(p)(x-h)
vertex is (h,k)
and
p is distance from focus to vertex, also distance from vertex to directrix
if p>0, then it opens to the right and directrix is to the left of vertex
if p<0, then it opens to the left and directrix is to the right of vertex
so
(y-1)²=4(4)(x-(-3))
vertex is (-3,1)
4>0 so directrix is to left of vertex
left is in x direction
-3-4=-7
directrix is x=-7
the answer is
x=-7
see the attached figure
if the y terms is squared so it opens left or right
Is a Horizontal Parabola, the equation is of the form
(y-k)²=4(p)(x-h)
vertex is (h,k)
and
p is distance from focus to vertex, also distance from vertex to directrix
if p>0, then it opens to the right and directrix is to the left of vertex
if p<0, then it opens to the left and directrix is to the right of vertex
so
(y-1)²=4(4)(x-(-3))
vertex is (-3,1)
4>0 so directrix is to left of vertex
left is in x direction
-3-4=-7
directrix is x=-7
the answer is
x=-7
see the attached figure
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Answer:
Solution given:
1:
-1/8=
2. -64/27
=
Express in rational number
1. (-3/2)=-3/2*2/2=-(3*2)*(2/2)=-6/4
2. (1/5)=1/5*5/5=<u>5/25</u>
and
(-4/3)³(2/5)-⁴ ÷ (7/4)
(-4³/3³)(2-⁴/5-⁴)÷7/4
(-64/27)(5⁴/2⁴)÷7/4
(-64/27)(625/16)÷7/4
(-64*625/(27*16))*4/7
-2500/27*4/7
-10000/169
(-100/13)²