Answer:
C =(43/55)R; C - R = 8t; 48 mi
Step-by-step explanation:
Let C = the distance a coyote can run in t hours.
Let R = the distance a rabbit can run in t hours.
(1) C = 43t
(2) R = 35t
A. <em>Two equivalent expressions
</em>
(a) C/R = 43/35
C = (43/55)R
(b) C – R = 43t – 35t
C – R = 8t
B. <em>Distance advantage of coyote
</em>
Let the difference D = C - R
D = 8t
D = 8 × 6
D = 48 mi
In 6 h, the coyote can run 48 mi further than the rabbit.
Well she cant have even amounts of beads so she must either have 12.5 beads or 13 reds and 12 blues or vise versa depending on if half beads are aloud
Answer:
It's C
Explanation: I don't need to give you an explanation >:(
The correct answer for this question is this one: <span>(-4, -11)
</span>In order to solve this,
Let k1 = 7/10 = fraction of the first part
Let k2 = 3/10 = fraction of the second part
Then, use solve for x and y
x = (k1(x2) +k2(x1)) / (k1+k2)
y = (k1(y2) +k2(y1)) / (k1+k2)
x = (7/10 * 5 + 3/10 * -25) / (7/10 + 3/10 )
<span>x = -8 / 2
x = -4
y = (7/10 * -25 + 3/10 * 10) / (7/10 + 3/10)
y = -14 + 3
y = -11
Hope this helps answer your question. Have a nice day!</span>
Answer:
120 miles
Step-by-step explanation:
Formulate equations.
Distance = rate * time.
D1 = distance from home to airport
D2 = distance from airport to off
D1 + D2 = 150
30 x t1 + 60 x t2 = 150
Divide through by 30
t1 + 2t2 = 5 ----- equation 1
Entire trip took 3 hours
t1 + t2 = 3 -------------------- equation 2
Solve equation 1 and 2 and you get
t1 = 1 hour
t2 = 2 hour
D2 = t2 x speed = 2 x 60
= 120 miles.
