All categories

4 years ago

Using Newtons first and thrid laws, explain what happens when you dribble a basketball

1 answer:

5 0

When you dribble a basket ball, it bounces because you move it. If you didn't move it, it wouldn't move. This is because objects are LAZY. Newtons first law is an object will remain still until it gets moved. I hoped this helped!

You might be interested in

A uniform steel plate has an area of 0.819 m2. When subjected to a temperature difference between its sides, a heat current* of

Tju [1.3M]

Answer:

ΔT / Δx = 771 K/m

ΔT = 771 x 0.0475 = 36.62 k

Explanation:

P = 31700 W, A = 0.819 m^2, Δx = 0.0475 m, K = 50.2 W /m k

Use the formula of conduction of heat

H / t = K A x ΔT / Δx

So, ΔT / Δx = P / K A

ΔT / Δx = 31700 / (50.2 x 0.819)

ΔT / Δx = 771 K/m

Now

ΔT = 771 x 0.0475 = 36.62 k

5 0

3 years ago

The radii of curvature of a biconvex lens are 4 cm and 15 cm. The lens is in air, its index of refraction is 1.5. An object is a

rewona [7]

Answer:

v = 6.315 cm

Explanation:

given,

R₁ = 4 cm = 0.04 m

R₂ = 15 cm = 0.15 m

n =1.5

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}=(n-1)(\dfrac{1}{R_1}-\dfrac{1}{R_2})$

$\dfrac{1}{v}-\dfrac{1}{-1}=(1.5-1)(\dfrac{1}{0.04}+\dfrac{1}{0.15})$

$\dfrac{1}{v}+1 = 0.5 \times 31.66$

$\dfrac{1}{v} = 15.833$

v = 0.06315 m

v = 6.315 cm

hence, the distance of the image from the back surface is v = 6.315 cm

8 0

3 years ago

15. The frequency of a wave is measured in which of the following units?

Bond [772]

Answer:

The frequency of a wave is measured in Hz (hertz)

6 0

3 years ago

You take a lab battery and, when it isn't connected to a circuit, you measure a voltage of 4.00-V with a voltmeter. You then con

max2010maxim [7]

Answer:

$r = 28.6 ohm$

Explanation:

As we know that when battery is in open circuit then the potential difference of the cell is known as EMF

so EMF is given as

$EMF = 4.00 V$

now when the battery is connected across a resistance of 200 ohm then there is current flowing through the battery

it is given as

$i = \frac{V}{R + r}$

$17.5 \times 10^{-3} = \frac{4}{200 + r}$

$200 + r = 228.6$

$r = 28.6 ohm$

6 0

4 years ago

The electric field strength E₀ is measured at a perpendicular distance R from an infinitely large, thin sheet that contains a un

Troyanec [42]

Answer:

Explanation:

E=(σ/ε0)

As noted by Dirac the field is the same no matter how far you are from the sheet. When your charge covers a conducting plane, as in your case, the field is, D/eo ,(D is charge density). Because the field inside the conductor (no matter how thin) is zero. The only time the field is, D/2eo, is when you have just a sheet of charge, by itself, not on a conducting plane."

5 0

4 years ago