Question

If a stone with an original velocity of zero is falling from a ledge and takes eight seconds that it the ground what is the final velocity at the stone

Answer 1

Answer: 78.4 m/s

The formula for speed using known acceleration:

$v=at+v_0=gt+v_0$

where the initial velocity v0 = 0 in this case, g is the gravitational acceleration and t is given to be 8 seconds, so:

$v = 9.8 \frac{m}{s^2}\cdot 8 s=78.4 \frac{m}{s}$