Is an enhancement of the bump mapping<span> or normal </span>mapping<span> techniques applied to textures in 3D rendering applications such as video games.</span>
Nuclear power generates large amounts of power with limited production of greenhouse gases.
is the answer
<u>Answer:</u>
For 1: The correct option is Option C.
For 3: The final velocity of the opponent is 1m/s
<u>Explanation: </u>
During collision, the energy and momentum remains conserved. The equation for the conservation of momentum follows:
...(1)
where,
are the mass, initial velocity and final velocity of first object
are the mass, initial velocity and final velocity of second object
<u>For 1:</u>
We are Given:

Putting values in equation 1, we get:

Hence, the correct answer is Option C.
Impulse is defined as the product of force applied on an object and time taken by the object.
Mathematically,

where,
F = force applied on the object
t = time taken
J = impulse on that object
Impulse depends only on the force and time taken by the object and not dependent on the surface which is stopping the object.
Hence, the impulse remains the same.
Let the speed in right direction be positive and left direction be negative.
We are Given:

Putting values in equation 1, we get:

Hence, the final velocity of the opponent is 1m/s and has moved backwards to its direction of the initial velocity.
Answer:
The speed of the block is 8.2 m/s
Explanation:
Given;
mass of block, m = 2.1 kg
height above the top of the spring, h = 5.5 m
First, we determine the spring constant based on the principle of conservation of potential energy
¹/₂Kx² = mg(h +x)
¹/₂K(0.25)² = 2.1 x 9.8(5.5 +0.25)
0.03125K = 118.335
K = 118.335 / 0.03125
K = 3786.72 N/m
Total energy stored in the block at rest is only potential energy given as:
E = U = mgh
U = 2.1 x 9.8 x 5.5 = 113.19 J
Work done in compressing the spring to 15.0 cm:
W = ¹/₂Kx² = ¹/₂ (3786.72)(0.15)² = 42.6 J
This is equal to elastic potential energy stored in the spring,
Then, kinetic energy of the spring is given as:
K.E = E - W
K.E = 113.19 J - 42.6 J
K.E = 70.59 J
To determine the speed of the block due to this energy:
KE = ¹/₂mv²
70.59 = ¹/₂ x 2.1 x v²
70.59 = 1.05v²
v² = 70.59 / 1.05
v² = 67.229
v = √67.229
v = 8.2 m/s