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shtirl [24]
4 years ago
8

When you divide , we are

Mathematics
2 answers:
fomenos4 years ago
5 0
Could you be a little more specific.
strojnjashka [21]4 years ago
3 0
Could you restate the question in a different way
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Consider the sum 36+45 . use the distributive property to rewrite the sum as the product of a whole number other than 1 and a su
IgorLugansk [536]

Answer:

9(4 +5)

Step-by-step explanation:

there is a common factor of 9 in both 36 and 45

9*4 = 36

9*5 = 45

by factoring 9 out of both 36 and 45, we get 9(4 + 5)

7 0
4 years ago
Hhhhjklkgjhhjklhkjhkjlhkjh
Karolina [17]

Answer:

hhughjHIBJYBJ8PPJJO00PKSOS

6 0
3 years ago
Read 2 more answers
15 people received an email and sent it to 3 different friends each, who in turn each sent it to 2 new people. What percent of t
pashok25 [27]

The original 15 people are 10% of the total number of people who received the mail.

Step-by-step explanation:

Given,

Number of people who received mail = 15

Mail further sent to 3 more friends;

Number of people who received mail from 15 people = 15*3 = 45 people

Number of people who received mail from 45 people = 45*2 = 90 people

Total number of people = 15+45+90 = 150 people

Now,

Percent of original people = \frac{Number\ of\ original\ people}{Total\ number\ of\ people}*100

Percent of original people = \frac{15}{150}*100=10\%

The original 15 people are 10% of the total number of people who received the mail.

Keywords: multiplication, percentage

Learn more about percentages at:

  • brainly.com/question/11018983
  • brainly.com/question/11145277

#LearnwithBrainly

8 0
4 years ago
A production supervisor at a major chemical company wishes to determine whether a new catalyst, catalyst XA-100, increases the m
zheka24 [161]

Answer:

a. n= 47

b. n= 128

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the new catalyst, XA-100, increases the mean hourly yield of a chemical process, that is known to be μ=750 (pounds per hour) with the current process.

You need to calculate the sample size to estimate the population with determined error margins.

To do so, since you have no population information, only that it is approximately normal distributed, you'll use the Student t statistic to get the sample size.

The formula of the margin of error (d) is:

d= t_{n-1: 1-\alpha/2} * (\frac{S}{\sqrt{n} })

I've  cleared the sample size of the formula

n= (S*\frac{t_{n-1; 1-\alpha /2} }{d} )^{2}

You need a sample size for the t-Student value and a standard deviation, that's why the information of a pilot study with n=5 and S= 19.62 is given.

a)

95% CI

d= 8 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.025}  = t_{4;0.975} =2.776

n= (19.62*\frac{2.776 }{8} )^{2}

n= 46.35 ≅ 47

b)

99% CI

d= 5 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.005}  = t_{4;0.995} =4.604

n= (19.62*\frac{4.604}{8} )^{2}

n= 127.49 ≅ 128

I hope it helps!

4 0
3 years ago
I-Ready find the measure of angle RST
garik1379 [7]

Answer:

Step-by-step explanation:

You need an image for problem to be solved, please repost it with a image, so it can be solved

3 0
3 years ago
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