Question

What is the equation of the axis of symmetry for this function? H(x) = -X2 + 10x - 11 x = -5 0 x= -10 x = 5 x = 10

Answer 1

Given:

The equation of a quadratic function is:

$H(x)=-x^2+10x-11$

To find:

The equation of the axis of symmetry for the given function.

Solution:

If a quadratic function is $f(x)=ax^2+bx+c$, then the equation of the axis of symmetry is:

$x=-\dfrac{b}{2a}$        ...(i)

We have,

$H(x)=-x^2+10x-11$

Here, $a=-1,b=10,c=-11$. So, the equation of axis of symmetry by using (i), is

$x=-\dfrac{10}{2(-1)}$

$x=-\dfrac{10}{-2}$

$x=5$

Therefore, the correct option is C.