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3 years ago

What’s the actual distance = yards?

Mathematics

2 answers:

laiz [17]3 years ago

8 0

The legend says 1 inch = 30 yards.

Multiply the total inches by 30 yards:

4 inches x 30 yards = 120 total yards.

AlekseyPX3 years ago

6 0

Answer:

1 inch = 30 yards

If you’re trying to figure out how many yards is 4 inches, you multiply 30 by 4. Your answer should be 120 yards

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Which of the following expresses 16 + 36 by using the GCF of the two numbers?

sergij07 [2.7K]

16 + 36 = 52 so the answer would be A) 4(4 + 9) because that equals 52 as well.

6 0

3 years ago

Read 2 more answers

Nisha collects comic books, and she convinced her friend Hakim to start collecting as well. Every week, they go to the store tog

andreyandreev [35.5K]

By using the given table, we will get the linear equation:

h = n - 9

<h3>How to find the equation for Hakim?</h3>

We know that they always get comic books together, so always that Nisha's collection increases by one, Hakim's collection will also increase by one, so we will have a linear equation.

Now, if you look at the given table, you can see that Hakim's collection is always 9 units less than Nisha's collection, then the linear equation that models the relation between the two collections, h and n, is really straightforward, it will be:

Hakim's collection = Nisha's collection - 9

Using the variables, we get:

h = n - 9

That is the linear equation Hakim wanted.

If you want to learn more about linear equations:

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6 0

1 year ago

6x+18y=18 find y and z

Masja [62]

6x + 18y = 18. Let us take x = 0

6(0) + 18y = 18

0 + 18y = 18

18y = 18

y = 18/18

y = 1

(0, 1) [x = 0, y = 1]

6x + 18y = 18. Let us take y = 0

6x + 18(0) = 18

6x + 0 = 18

6x = 18

x = 18/6

x = 3

(3, 0) [x = 3, y =0]

Infinite solutions can be found for x and y

3 0

3 years ago

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

$\mu_s=np=500*0.90=450$

The standard deviation will be:

$\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7$

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

$z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932$

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

$\mu=np=300*0.932=279.6$

The standard deviation will be:

$\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36$

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

$P(270\leq x\leq280)=P(269.5$