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Ghella [55]
3 years ago
5

What’s the actual distance = yards?

Mathematics
2 answers:
laiz [17]3 years ago
8 0

The legend says 1 inch = 30 yards.

Multiply the total inches by 30 yards:

4 inches x 30 yards = 120 total yards.

AlekseyPX3 years ago
6 0

Answer:

1 inch = 30 yards

If you’re trying to figure out how many yards is 4 inches, you multiply 30 by 4. Your answer should be 120 yards  


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190 divided by 95 simplified
Roman55 [17]
190 divided by 95 is 2. 
8 0
3 years ago
A line has a y-intercept of -10 and a slope of 7/4 Find the equation of the line.
Gwar [14]

Answer:

(7/4)x - 10

Step-by-step explanation:

y = mx + c

m = gradient

c = y-intercept

so you just substitute in the respective values

6 0
2 years ago
2(n+5)= -2 I need the full explination
lakkis [162]

Answer:

n=-6

Step-by-step explanation:

2n + 10 = -2

2n=-12

n=-6

Hope this helps!

If not I'm sorry.

3 0
2 years ago
Read 2 more answers
A rectangular plot measures 20 ft. By 30ft. A 3ft wide side walk surrounds it. Find the area of the side walk
r-ruslan [8.4K]

Answer:

336 feet²

Step-by-step explanation:

If we have a rectangle that is 30 by 20 feet, that means the area of that rectangle would be 20 × 30 feet squared, which is 600 ft².

If there is a 3 feet sidewalk surrounding it, that means that the end of the sidewalk will extend 3 feet extra around each side of plot. Since there are two ends to one side, that means an extra six feet is added on to each dimension. Therefore, 36 × 26 are the dimensions of the sidewalk+plot. 36 × 26 = 936 ft².

To find the area of the sidewalk itself, we subtract 600 ft² from 936 ft². This gets us with 336 ft².

Hope this helped!

3 0
2 years ago
What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti
Marat540 [252]

Answer:

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}

x = \frac{5 \± \sqrt{25 +28}}{2}

x = \frac{5 \± \sqrt{53}}{2}

Split the expression to two

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

x = \frac{12.28}{2}  or  x = \frac{-2.28}{2}

x = 6.14 or x = -1.14

4 0
3 years ago
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