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Hatshy [7]
4 years ago
13

Bob has 99 dimes and quarters worth $21. How many of each does he have

Mathematics
1 answer:
prohojiy [21]4 years ago
5 0

Answer:

Step-by-step explanation:

d + q = 99.....d = 99 - q

0.10d + 0.25q = 21

0.10(99 - q) + 0.25q = 21

9.9 - 0.10q + 0.25q = 21

-0.10q + 0.25q = 21 - 9.9

0.15q = 11.1

q = 11.1 / 0.15

q = 74 <===== he has 74 quarters

d = 99 - q

d = 99 - 74

d = 25 <=== he has 25 dimes

check...

0.10d + 0.25q = 21

0.10(25) + 0.25(74) = 21

2.50 + 18.50 = 21

21 = 21 (correct)

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