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Oduvanchick [21]
3 years ago
15

What is the image of the point (-1,9) after a rotation of 180 counterclockwise about the origin?

Mathematics
1 answer:
Oxana [17]3 years ago
7 0

Answer:

(1,-9)

Step-by-step explanation:

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Triangle DEF is a right triangle. What is the measure of ZEFD?<br> D<br> 57°<br> F<br> E
creativ13 [48]

Answer:

<h3>                33°</h3>

Step-by-step explanation:

Sum of measures of angles in any triangle is 180°

The maesure of right angle is 90°

So:  m∠EFD = 180° - 90° - 57° = 33°

6 0
3 years ago
An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
12−5x−4kx=y solve for x
IrinaVladis [17]
Minus 12 both sides
-5x-4kx=y-12
undistribute x
x(-5-4k)=y-12
divide both sides by (-5-4k)
x=\frac{y-12}{-5-4k}
x=\frac{12-y}{4k+5}
5 0
3 years ago
Read 2 more answers
Y = -8x – 3<br> x+y=7<br> Is (3, 4) a solution of the system?
77julia77 [94]
4 = -8(3) - 3
4 = -24-3 false

3 + 4 = 7 true

The first one is false, second is true
5 0
3 years ago
Read 2 more answers
What are the vertices of /(△)?
Serga [27]

Answer:

3!

Step-by-step explanation:

The vertices are the points of the triangle. So if you count each point you get 3!

8 0
3 years ago
Read 2 more answers
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