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Rashid [163]
3 years ago
13

Y = 3x + 1 y = 3x - 3 Please help me out what’s x? What’s y?

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

Step-by-step explanation:

use the comparison method

3x + 1 = 3x - 3

1 = -3

the expression is false for any value of x and y , so there no solution

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The first and last terms of a 52-term arithmetic series are listed in the table. What is the sum of the series?
PilotLPTM [1.2K]

Answer: 4030

Step-by-step explanation:

We know that sum of an arithmetic series with first term as 'a' and the last term as 'l' is given by :-

S_n=\frac{n}{2}(a+l), where n is the number of terms

In the given situation, the number of terms = 52

The first term = 1

The 52th term = 154

Then the sum of 52 terms ids given by :-

S_{52}=\frac{52}{2}(1+154)\\\Rightarrow\ S_{52}=(26)(155)=4030

Hence, the sum of the series =4030

7 0
3 years ago
Read 2 more answers
Using principle of mathematical induction prove that 6^-1 divisble by 5 .​
salantis [7]

I suppose the claim is 5 \mid 6^n - 1 for n\in\Bbb N.

When n=1, we have 6^1 - 1 = 6 - 1 = 5, and of course 5 divides 5.

Assume the claim holds for n=k, that 5 \mid 6^k - 1. We want to use this to show it holds for n=k+1, that 5 \mid 6^{k+1} - 1.

We have

6^{k+1} - 1 = \left(6^{k+1} - 6\right) + \left(6 - 1) = 6\left(6^k - 1\right) + 5

Since 5 \mid 6^k - 1, we can write 6^k - 1 = 5\ell for some integer \ell. Then

6^{k+1} - 1 = 6\cdot5\ell + 5 = 5(6\ell + 1)

which is clearly divisible by 5. QED

5 0
1 year ago
What is the Ratio of 472 and 482?
Lemur [1.5K]
The answer to your question is

answer: 236/241

❤️❤️!!
8 0
3 years ago
Read 2 more answers
The graph of an exponential function passes through the point (0,15) and (1,10). What is the equation of the exponential functio
Vilka [71]

Answer:

y=15(\frac{2}{3})^x

Step-by-step explanation:

we know that

The equation of a exponential function is of the form

y=a(b^x)

where

a is the initial value or y-intercept

b is the base of the exponential function

In this problem we have

a=15 ----> the y-intercept is given

substitute

y=15(b^x)

we have the other ordered pair (1,10)

substitute the value of x and the value of y and solve for b

10=15(b^1)\\10=15b

b=\frac{10}{15}=\frac{2}{3}

substitute

y=15(\frac{2}{3})^x

see the attached figure to better understand the problem

7 0
3 years ago
Can sum1 explain on how to do 1 &&' 2
HACTEHA [7]

what times it self is 36 answer the square root of 86

the same for the second 1

6 0
3 years ago
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