What is the approximate value of log 12 if log 2 =0.301, log 3 =0.477, and log 6 = 0.778
1 answer:
Answer:1.079
Step-by-step explanation:
We know that log a +log b = logab
Using this rule, we will find log12.
Log6 + log2= log12
.778 + .301 = 1.079
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