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2 years ago

The measurement of one angle of a right triangle is 61°.

Mathematics

2 answers:

Katyanochek1 [597]2 years ago

5 0

All the interior angles of a triangle added up is 180 degrees

180-61-90(given a right triangle)=

90-61=

Free_Kalibri [48]2 years ago

4 0

29 degrees since the sum of all the angles of a right triangle has to be 180 degrees

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Find the missing side length.

MaRussiya [10]

x = 6

Explanation:

use the pythagorean theorem which is <u>a^2 + b^2 = c^2</u>. 8 goes in either the a or b position and 10 is the longest side so it will go in the c position.

8 0

3 years ago

Grant spent 2.50,$4.00,$4.25, and $3.25?On breakfast one week.The next week he spent $6 more in total for the 4 breakfasts than

masha68 [24]

We have been given that Grant spent $2.50, $4.00, $4.25, and $3.25 on breakfast in one week. The next week he spent $6 more in total for the 4 breakfasts than the week before. We are asked to find increase in the mean of second week.

Since Grant spent $6 more than last week, we will divide 6 by 4 to get how much mean of second week breakfast expenditures increased with respect to first week expenditures.

$\text{Mean increase in second week breakfast expenditure}=\frac{6}{4}$

$\text{Mean increase in second week breakfast expenditure}=1.5$

Therefore, mean of second week breakfast expenditure will be $1.5 more than first week.

3 0

3 years ago

a gallon of chocolate milk sells for $3.14. a snack-size bottle of chocolate milk sells for 3 cents per ounce. which is a better

Yuliya22 [10]

A snack-size bottle of chocolate milk is better because it cost less.

6 0

3 years ago

Read 2 more answers

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

3 years ago

(x-yi)(3+5i) is the conjugate of 6+24i

Nataly_w [17]

Answer:

x=-3

y=3

(-3-3i)(3+5i)

Step-by-step explanation:

$(x-yi)(3+5i)\\=3x+5xi-3yi+5y\\=(3x+5y)+(5x-3y)i\\$

and we have that must equal

6-24i

3x+5y=6

5x-3y=-24 and if we work it we found out that the solutions are

x=-3 and

y=3

5 0

3 years ago