Question

The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = –x + 6. What is the point-slope form of the equation for this line?
y – 3 = –(x + 8)
y + 3 = –(x – 8)
y + 8 = –(x – 3)
y – 8 = –(x + 3)

The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3) is y – 3 = (x – 1). What is the slope-intercept form of the equation for this line?
y = x + 2
y = x – 4
y = x +
y = x –

The point-slope form of the equation of the ...

Answer 1

Y = mx + b is  the "slope-intercept" form of the equation of a line ;
We have y = -x + 6 ;
Then, m = - 1 ;

The "point-slope" form of the equation of a straight line is:
y - y1 = m(x - x1) ; 
But, x1 = - 3 and y1 = 8 ;
We have y - 8 = (-1)( x + 3 );
Finally, y - 8 = -( x + 3 );
 The right answer is the fourth choice;
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y – 3 = (x – 1) ; the equation becames

y = x + 2 ; 
The right answer is the third choice;

Answer 2

Answer:

The third one :)