The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = –x + 6. What is the point-slope form
of the equation for this line? y – 3 = –(x + 8)
y + 3 = –(x – 8)
y + 8 = –(x – 3)
y – 8 = –(x + 3)
The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3) is y – 3 = (x – 1). What is the slope-intercept form of the equation for this line?
y = x + 2
y = x – 4
y = x +
y = x –
Y = mx + b is <span> the "slope-intercept" form of the equation of a line ; We have y = -x + 6 ; Then, m = - 1 ;
</span><span>The "point-slope" form of the equation of a straight line is: </span><span>y - y1 = m(x - x1) ; But, x1 = - 3 and y1 = 8 ; We have y - 8 = (-1)( x + 3 ); Finally, y - 8 = -( x + 3 ); The right answer is the fourth choice; ________________________________________
</span><span>y – 3 = (x – 1) ; the equation becames </span> y = x + 2 ; The right answer is the third choice;
