All categories

2 years ago

I need help please for my test

Mathematics

1 answer:

Umnica [9.8K]2 years ago

7 0

original figure (-7,-6)

final figure (-7,2)

You might be interested in

I need help with these 2 math problems 1) -3 3/8 x 6= 2) 7/9 x 6=

earnstyle [38]

1) -34 which is very simple
2) 4 2/3

6 0

3 years ago

Read 2 more answers

10. The expression 4 (2x-5)+7(x+2) can be written in simplest form as

ankoles [38]

Answer:

15x-6

Step-by-step explanation: 4 * 2x = 8x

4*-5 = -20

7*x = 7x

7*2= 14

Combine like terms 8x + 7x + 14-20

15x-6

4 0

2 years ago

A bottle holds 5/12 gallon of water. How many bottles can be filled with 2 1/4 gallons of water?

tekilochka [14]

Answer: 0.185 gallons

Step-by-step explanation:

Divide 5/12 by 2 1/4

First convert the improper fraction to a proper fraction, 2 1/4 = 9/4

5/12 ÷ 9/4

= 5/12 × 4/9

= 5/27 = 0.185

6 0

3 years ago

HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH

8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

$4+\sqrt{6x}$

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

$4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}$

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

$\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}$

Thank you

8 0

3 years ago

Una superficie mide 400 cm de largo y 360 cm de ancho. Se quiere dividir en cuadrados que tengan la mayor área posible y que la

victus00 [196]

Answer:

https://scuolaelettrica.it/correttore/spagnolo/manutenzione/risolutore/risolti/risoltirettangolo.php

Step-by-step explanation:

here use this

5 0

2 years ago