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marishachu [46]
3 years ago
13

Naomi‘s fish is 40 mm long. Her guinea pig is 25 cm long. How much longer is your guinea pig than her fish?

Mathematics
1 answer:
hjlf3 years ago
3 0

Answer:

21 cm

Step-by-step explanation:

25-4=21

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Which of the following expressions is equal to 5^6/5^2
Natali5045456 [20]

Answer:

\dfrac{5^6}{5^2} = 5{\cdot}5{\cdot}5{\cdot}5

Step-by-step explanation:

The given expression is :

\dfrac{5^6}{5^2}

We need to find this expression is equal to what.

\dfrac{5^6}{5^2}=\dfrac{5^4\times 5^2}{5^2}\\\\=5^4\\\\=5\times 5\times 5\times 5\\\\\text{or}\\\\=5{\cdot}5{\cdot}5{\cdot}5

Hence, \dfrac{5^6}{5^2} is equal to 5{\cdot}5{\cdot}5{\cdot}5. Hence, the correct option is (c).

5 0
3 years ago
What is the value of p? 13^2=p Iready
pashok25 [27]

Answer:

I believe the answer is p=169?

Step-by-step explanation:

13^2 is 13×13 which equals 169

8 0
3 years ago
Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G
Kaylis [27]

\Rightarrow

Suppose first that H\subset G is a normal subgroup. Then by definition we must have for all a\in H, xax^{-1} \in H for every x\in G. Let a\in G and choose (ab)\in aH (b\in H). By hypothesis we have aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H, i.e. aba^{-1}=c for some c\in H, thus ab=ca \in Ha. So we have aH\subset Ha. You can prove Ha\subset aH in the same way.

\Leftarrow

Suppose aH=Ha for all a\in G. Let h\in H, we have to prove  aha^{-1} \in H for every a\in G. So, let a\in G. We have that ha^{-1} =a^{-1}h' for some h'\in H (by the hypothesis). hence we have aha^{-1}=h' \in H. Because a was chosen arbitrarily  we have the desired .

 

5 0
3 years ago
Condense the expression log 2x + log(x² - 9) - log x +3
Rudik [331]
Here the my solutions,hope you understand

4 0
2 years ago
The black figure is an ellipse, and the black line segment is is major axis. What is the length of the blue line segment?
NeTakaya

Answer:

D

Step-by-step explanation:

The formula we need to solve this is:

d_1+d_2=2a

Where

d_1  is the distance from one focus to the vertex

d_2  is the second distance from another focus to same vertex

<u>Note:</u> Here, vertex point is the point on top. The common point from which the RED and BLUE line meets the 2 foci

a  is half the length of the major axis (which is 9 here since total major axis is given as 18)

<em>Now we can plug into the equation and solve:</em>

<em>d_1+d_2=2a\\8.5+d_2=2(9)\\8.5+d_2=18\\d_2=18-8.5\\d_2=9.5</em>

<em />

<em>D is the correct answer.</em>

6 0
3 years ago
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