What does the Internet Engineering Task Force (IEFT) do?

Computers and Technology

2 answers:

emmasim [6.3K]3 years ago

7 0

Answer: The answer is creates methods of moving files between computers and networks.

noname [10]3 years ago

6 0

The answer is creates methods of moving files between computers and networks.

The IEFT is an open standard body that defines standard Internet protocols like TCP/IP and promotes and develops these protocols. It consists of a large community of operators, network engineers, and vendors concerned with the evolution of the smooth operation of the internet. When we talk about internet standards, we are talking about areas that have always been a major concern to the IEFT like Application, internet, routing, security, management and operational, and many others.

You might be interested in

Jensen is a senior developer for Hackers R'Us, a company that helps secure management information systems. Jensen's new task is

Harlamova29_29 [7]

Answer:

b. white-hat hacker

Explanation:

A White-hat Hacker, also known as an Ethical Hacker is an information security specialist, known for performing penetration testing and checks in search for information and communications system's vulnerabilities on demand for his/her clients.

These efforts are meant to find security risks before someone else does, who could cause any kind of damage to the systems or unauthorized access to sensitive information

6 0

3 years ago

a password to a certain database consists of digits that cannot be repeated. if the password is known to consist of at least 8 d

BaLLatris [955]

Answer:

$\frac{10!}{2}mins$

Explanation:

12 seconds to try one combination will be equivalent to $\frac{1}{12}\times 60 = \frac{1}{5} \ mins$

Password contain at least 8 digit i.e. password can contain 8, 9, 10 digit.

Password cannot contain more than 10 digit because it will give room for repetition which it is clearly stated that digit cannot be repeated.

Possible digit that can be used: 9,8,7,6,5,4,3,2,1,0.

Total number of passwords combination possible for each position in 8 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3. Total number of passwords combination possible in 8 digit is equivalent to $\frac{10!}{2}$ .

Total number of passwords combination possible for each position in 9 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2. Total number of passwords combination possible in 9 digit is equivalent to $\frac{10!}{1}$ .

Total number of passwords combination possible for each position in 10 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2, 10th position = 1. Total number of passwords combination possible in 10 digit is equivalent to 10!.

Adding them up and multiplying by $\frac{1}{5} \ mins$ to get the total number of time needed to guarantee access to database = $[\frac{10!}{2}\times\ \frac{10!}{1} \times 10!] \frac{1}{5}\ mins = \frac{10!}{2}$