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Alekssandra [29.7K]
3 years ago
10

A virus that propagates using the internet or another computer network is called __________.

Computers and Technology
1 answer:
olasank [31]3 years ago
8 0
This is called a worm
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Create html code showing heading tags​
kow [346]

Answer:

Assuming you mean the HTML5 head tag, then this may work for you:

<!DOCTYPE HTML>

<html lang="en">

<head>

<title>My Very Awesome Website</title>

<link href="./css/main.css" rel="stylesheet"  />

<meta name="viewport" content="width=device-width, initial-scale=1" />

</head>

<body>

<h1>Hey look</h1>

<p>This is my awesome website!</p>

<h3>Note</h3>

<p>This website is supposed to be 100% awesome!</p>

</body>

</html>

3 0
3 years ago
What are the main differences between openldap and microsoft's active directory (ad)? check all that apply
nikklg [1K]

The main differences between openldap and microsoft's active directory are:

  • Open LDAP works on any OS, AD does not.
  • Open LDAP is open-source, AD is not.

<h3>What is the openldap and microsoft's active directory?</h3>

The LDAP is known to be a kind of an open, vendor-agnostic that functions  with a lot of directory services, such as AD. AD but Microsoft's proprietary directory service is known to often put together a lot of IT assets like computers and its users.

Therefore, The main differences between openldap and microsoft's active directory are:

  • Open LDAP works on any OS, AD does not.
  • Open LDAP is open-source, AD is not.

Learn more about  active directory from

brainly.com/question/24215126

#SPJ12

6 0
2 years ago
Write a Java method onlyDigits that takes a string as a parameter. The method should remove from the string all characters, whic
Stels [109]

Answer:

public static String onlyDigits(String in){

    String digitsOnly = in.replaceAll("[^0-9]", "");

    return digitsOnly;

}

A Complete program is wrtten in the explanation section

Explanation:

public class TestClass {

   public static void main(String[] args) {

     String a = "-jaskdh2367sd.27askjdfh23";

       System.out.println(onlyDigits(a));

}

public static String onlyDigits(String in){

    String digitsOnly = in.replaceAll("[^0-9]", "");

    return digitsOnly;

}

}

The output: 23672723

The main logic here is using the Java replaceAll method which returns a string after replacing all the sequence of characters that match its argument, regex with an empty string

3 0
3 years ago
Complete the method, longestWord(), below that takes in an array of Strings and returns the longest String in the array. Note: y
beks73 [17]

Answer:

I am writing a JAVA program.

public class StringMethod {

public static String longestWord(String []words) { //method that takes an array  "word" of strings and returns the longest string in the array word

    int pos = 0; // contains index of the longest word of array words

    int longest = words[0].length(); //initially holds the length of the 1st element of words array

    for(int i=1; i< words.length; i++) { // iterates through each word of the array until the end of array

        if(words[i].length() > longest) { // if the length of word at i-th index of words[] is greater than the length of the word that is contained in longest variable

            pos = i; // assigns the index of the longest array element to pos

            longest = words[i].length();    } } //assigns the word in words[] array with the longest length to longest variable

   return words[pos]; } // returns the longest string in the array    

public static void main(String[] args) { //start of main() function body

String[] animals = {"cat", "horse", "elephant", "bird"}; //creates a String type array named animals which has 4 elements/words

   String longest_word= longestWord(animals); //calls longestWord method to find the longest string in the array animals and assign that longest string to longest_word.

  System.out.println(longest_word); }} //displays the longest word in output

Explanation:

Suppose we have the array of these elements: "cat", "horse", "elephant", "bird" These are four words in the array. Now lets see how the method longestWord() works:

int pos = 0; This variable is initialized to 0.

int longest = words[0].length();

longest holds the length of element at 0th index of words[] array. length() method is used to return the length of the first element words[0] array.

As the first element of array is "cat" so length of cat is 3. Hence longest = 3

for(int i=1; i< words.length; i++)

The loop has a variable i which is initialized to 1. The loop checks if the value of i is less than length of words[] array. The length of words array is 4 as there are 4 elements i.e. cat, horse, elephant and bird in this array. So the condition evaluates to true because i<words.length i.e. 1<4. The body of the loop will execute now. The body of loop contains an if condition if(words[i].length() > longest) which checks if the length of element of array at i-th index is greater than length of the element that is stored in longest variable. As i=1 so word[i] is word[1] which is the second element of words[] array. The second element is horse.

words[i].length()  means the length of i-th element of words[] array. So this means words[1].length() i.e. the length of element of words[] at 1st index. The length of horse is 5. So the statement if(words[i].length() > longest) is true because longest=3 and words[1].length() = 5 and 5>3. So the statements of if condition will execute now.

pos = i; this variable pos is used to hold the index position of the longest element in array. So pos = 1 as longest element computed so far is "horse".

longest = words[i].length(); This statement then assigns the length of horse to longest. So now the value of longest = 5

At second iteration i is now 2.  Loop condition evaluates to true because i<words.length i.e. 2<4. If condition is also true as i=2 so word[i] is word[2] which is elephant.

words[i].length() now means words[2].length() i.e. the length of element of words[] at 2nd index. The length of elephant is 8. So the statement if(words[i].length() > longest) is true because longest=5 and words[2].length() = 8 and 8>5. So the statements of if condition will execute now.

pos = i; now becomes pos = 2 as longest element computed so far is "elephant".

longest = words[i].length();  This statement then assigns the length of horse to longest. So now the value of longest = 8

At third iteration i is now 3.  The loop again checks if the value of i is less than length of words[] array.The condition evaluates to true because i<words.length i.e. 3<4. The body of the loop will execute now.  if(words[i].length() > longest) checks if the length of element of array at i-th index is greater than length of the element that is stored in longest variable. As i=3 so word[i] is word[3] which is the fourth element of words[] array. The fourth element is bird.

words[i].length() now means words[3].length() i.e. the length of element of words[] at 3rd index. The length of bird is 4. So the statement if(words[i].length() > longest) is false because longest=8 and words[2].length() = 4 and 4<8. So the statements of if condition will not execute now.

At fourth iteration i is now 4.  The loop again checks if the value of i is less than length of words[] array.The condition evaluates to false because i==words.length i.e. 4=4. So the loop breaks.

 return words[pos]; statement returns the index position of longest word in words[] array. pos = 2 So the array element at 2nd index is basically the third element of array words[] i.e. elephant. So the longest string in the array is elephant.

8 0
3 years ago
How to analyze time complexity of a code?
VladimirAG [237]

Answer:

we can multiply or divide by a constant factor to get to the simplest expression. The most common metric for calculating time complexity is Big O notation. This removes all constant factors so that the running time can be estimated in relation to N as N approaches infinity.

Explanation:

7 0
4 years ago
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