Let's begin with 2500 mm and convert this to cm.
2500 mm = 250 cm
Next, convert 250 cm to inches. Recall that 1 inch = 2.54 cm.
Then (250 cm)(1 inch) / (2.54 cm) = (250 cm) (1 in)/ (2.54 cm)
= (250/2.54) inches = ? inches
Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:
h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.
I think 7 would be the greatest common factor as they all have different variables. By factoring out 7 you should end up with, 2x+3y+z=