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dimulka [17.4K]
2 years ago
14

A factory produces a batch of toy vehicles, 1/3 of which are cars and the rest are trucks. trucks have defective ratio of 0.02 a

nd cars have defective ratio of 0.01. the quality inspector picks a toy vehicle at random from the batch and finds out that it is defective. what is the probability that the vehicle was a truck
Mathematics
1 answer:
krek1111 [17]2 years ago
4 0

Answer:

Step-by-step explanation:

b

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38. A baseball park's average game attendance is 2035 people. This is 65
marta [7]

Answer:

<u><em>1970</em></u> is the answer for the question "A baseball park's average game attendance is 2035 people. This is 65 more than the average attendance for last year. What was the average game attendance for last year?"

<u><em>- hope this helps!:)</em></u>

6 0
3 years ago
Please help i cant get this
Sveta_85 [38]

Answer:

0.264

Step-by-step explanation:

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2 years ago
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What is the sum of 1/3 + 5 3/4 as a mixed number in simplest form
mart [117]

6 1/12 would be the answer

Rewriting our equation with parts separated

1/3+5+3/4

Solving the fraction parts

1/3+3/4=?

Find the LCD of 1/3 and 3/4 and rewrite to solve with the equivalent fractions.

LCD = 12

4/12+9/12=13/12

Simplifying the fraction part, 13/12,

13/12=11/12

Combining the whole and fraction parts

5+1+1/12=6 1/12

3 0
3 years ago
Find the 52nd term of the following arithmetic sequence.<br> 17, 22, 27, 32, ...
rewona [7]

Answer:

17; 22; 27; 32

the terms increase by 5 each time

17 + 5 = 22 (the second term)

17 + 5 * 2 = 27 (third term)

So to get to the 52nd term, we have to add 5* 51 = 255 to 17

17 + 255 = 272

Step-by-step explanation:

4 0
3 years ago
5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
3 years ago
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